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3 years ago

The atmosphere has mass and produces friction as objects move through it. true or false

Physics

2 answers:

irina [24]3 years ago

4 0

true

Explanation:

It has friction when objects move through it.

olchik [2.2K]3 years ago

4 0

True

Explanation:
It has friction when objects move through it.

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Schach [20]

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3 years ago

Based on the diagram of the two electrical circuits, assuming the lightbulbs are all identical, which circuit will draw more pow

pochemuha

In series connection in orde to find the total resistance we add all the resistance capacity but in parallel, we take the 1/R and resistance = V hence the series connection takes up more power,

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4 years ago

How much force is required to produce a torque of 100 Nm if the force is applied at an angle of 40 at a distance of 25 cm from t

Fudgin [204]

Answer:

Force, F = 622.28 N

Explanation:

It is given that,

Torque, $\tau=100\ N-m$

Angle between force and displacement, $\theta=40^{\circ}$

Distance, d = 25 cm = 0.25 m

We need to find the force required to produce the torque. Torque produced by an object is given by :

$\tau=Fd\sin\theta$

F is force required to produce torque

$F=\dfrac{\tau}{d\sin\theta}\\\\F=\dfrac{100}{0.25\times \sin(40)}\\\\F=622.28\ N$

So, applied force is 622.28 N.

7 0

3 years ago

An air filter can remove dust particles from air but will reach capacity (saturation) at 50.0 mg. Of air containing 225 µg dust

zubka84 [21]

Answer:

Time to Reach Saturation = 0.0146 day

Explanation:

In order to solve this problem, we first need to calculate the dust filtered by the filter per cubic meter of air:

Filtered Dust per m³ = Dust Particles Entering per m³ - Dust Particles Leaving per m³

Filtered Dust per m³ = 225 μg/m³ - 15 μg/m³

Filtered Dust per m³ = 210 μg/m³ = 210 x 10⁻³ mg/m³

Now, we find volume flow rate of air through filter:

Volume Flow Rate of Air = (400 ft³/min)(0.3048 m/1 ft)³

Volume Flow Rate of Air = 11.33 m³/min

Now, we calculate rate of dust filtered:

Rate of Dust Filtered = (Filtered Dust per m³)(Volume Flow Rate of Dust)

Rate of Dust Filtered = (210 x 10⁻³ mg/m³)(11.33 m³/min)

Rate of Dust Filtered = 2.38 mg/min

Now, for the time required to reach saturation:

Time to Reach Saturation = (Saturation Capacity)/(Rate of Dust Filtered)

Time to Reach Saturation = (50 mg)/(2.38 mg/min)

Time to Reach Saturation = (21.02 min)(1 day/24 h)(1 h/60 min)

<u>Time to Reach Saturation = 0.0146 day</u>

3 0

4 years ago

5. Which one of the following factors is directly proportional to density of liquid? (a) Temperature (b) Volume of liquid (c) Up

FinnZ [79.3K]

Answer:

The upthrust on a floating body is in upwards direction and is equal to the weight of the liquid displaced

The upthrust is directly proportional to the density of the liquid in which the solid is immersed

The upthrust is directly proportional to the volume of the fluid displaced by a solid

The upthrust acts on the body in upward direction at the center of buoyancy.

Upthrust is equal to the weight of liquid displaced by object and weight of liquid will depend on its density.

Upthrust is F=Vρg ,where V is the volume of liquid displaced and ρ is the density of fluid.

The total lateral pressure acting on an immersed object on one side is equal and in opposite direction to the total lateral pressure acting on the other side.

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3 years ago