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Arada [10]
3 years ago
12

Why is U-235 the most common nuclear fuel instead of the more abundant U-238? State a clear topic sentence and support it with e

vidence.
Chemistry
1 answer:
GREYUIT [131]3 years ago
3 0
<h3><u>Answer and explanation</u>;</h3>
  • <em><u>The isotope U-235 is an important common nuclear fuel because under certain conditions it can readily be split, yielding a lot of energy. It is therefore said to be 'fissile' and use the expression 'nuclear fission'.</u></em>
  • <em><u>Uranium 238 on the other hand is not fissionable by thermal neutrons, but it can undergo fission from fast or high energy neutrons. Hence it is not fissile, but it is fissionable.</u></em>
  • In a nuclear power station fissioning of uranium atoms replaces the burning of coal or gas.  Heat created by splitting the U-235 atoms is then used to make steam which spins a turbine to drive a generator, producing electricity.
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2C2H2 + 5O2 → 4CO2 + 2H2O
umka21 [38]
The answer is -2512.4 kJ
8 0
3 years ago
What is one major difference between volcanic activity on Earth and volcanic activity on Mars, Venus, and the moon? Explain.
kow [346]

While the Moon and Mercury have relatively small volcanoes, those on Venus, Earth and Mars are large and numerous.  Earth's volcanoes are still active and Venus' may be, but scientists debate whether Mars' volcanic activity has finished.

8 0
3 years ago
80.0 grams of NaOH is dissolved in water to make a 6.00 L solution what is the molarity of the solution
Elanso [62]

Answer:

0.33 mol/ L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer will help you. Have a nice day !

3 0
3 years ago
Which of the following statements is true concerning an aqueous solution of the weak base NH3?
babunello [35]

Answer: Option (A) is the correct answer.

Explanation:

When weak base NH_{3} is dissolved in water then the reaction will be as follows.

       NH_{3} + H_{2}O \rightarrow NH^{+}_{4} + OH^{-}

When NH_{3} is compared with water then oxygen atom of H_{2}O being more electronegative in nature will keep its lone pair of electrons towards itself.

Hence, water will act as a neutral molecule and hence, NH_{3} will act as a stronger base as compared to H_{2}O.

On the other hand, OH^{-} will have both lone pair of electrons and a negative charge. Hence, its electron density is much more as compared to NH_{3} that only contains a lone pair of electron.

Therefore, NH_{3} will act as a weak base as compared to OH^{-}.

Thus, we can conclude that the statement OH^{-} is a stronger base than NH_{3}, is true concerning an aqueous solution of the weak base NH_{3}.

8 0
3 years ago
Calculate the entropy change in the surroundings associated with this reaction occurring at 25∘c.
gayaneshka [121]

This is an incomplete question, here is a complete question.

Consider the reaction between nitrogen and oxygen gas from dinitrogen monoxide.

2N_2(g)+O_2(g)\rightarrow 2N_2O(g)

Given: delta Hrxn= +163.2kJ

Calculate the entropy change in the surroundings when this reaction occurs at 25 degrees C.

Answer : The entropy change in the surroundings is, -547.6 J/K

Explanation :

Formula used to calculate the entropy change in the surroundings is:

\Delta S_{surr}=-\frac{Q}{T}

where,

\Delta S_{surr} = entropy change in the surrounding

Q = heat energy

T = temperature = 25^oC=273+25=298K

Given:

\Delta H_{rxn}=+163.2kJ

\Delta H_{rxn}=Q=+163.2kJ

Now put all the given values in the above formula, we get:

\Delta S_{surr}=-\frac{163.2kJ}{298K}

\Delta S_{surr}=-\frac{163.2\times 1000J}{298K}

\Delta S_{surr}=-547.6J/K

Therefore, the entropy change in the surroundings is, -547.6 J/K

4 0
3 years ago
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