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oee [108]
2 years ago
6

A body moving with an acceleration 2 m/s?then what is the change in velocity in 4sec.​

Physics
1 answer:
enot [183]2 years ago
7 0

Answer:

As Per Provided Information

Moving body has 2m/s² acceleration

Time taken by body is 4 second

We are asked to find the 'change in velocity' ( ∆V) by the body.

<u>Formula Used here</u>

\boxed{\bf{\Delta \: V \:  =  acceleration \:  \times time \:}}

<u>Substituting </u><u>the </u><u>given </u><u>value</u>

<u>\sf\longrightarrow\Delta\:V \:  = 2 \times 4 \\  \\  \\ \sf\longrightarrow\Delta\:V \:  =8m {s}^{ - 1}</u>

<u>Therefore</u><u>,</u>

  • <u>Change </u><u>in </u><u>velocity </u><u>is </u><u>8</u><u> </u><u>m/</u><u>s</u>
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Say the tortoise and the hare are racing. If the tortoise moves straight
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An oxygen molecule is adsorbed onto a small patch of the surface of a catalyst. It's known that the molecule is adsorbed on of p
FromTheMoon [43]

The given question is incomplete. The complete question is as follows.

An oxygen molecule is adsorbed onto a small patch of the surface of a catalyst. It's known that the molecule is adsorbed on 1 of 36 possible sites for adsorption. Calculate the entropy of this system.

Explanation:

It is known that Boltzmann formula of entropy is as follows.

             s = k ln W

where,   k = Boltzmann constant

              W = number of energetically equivalent possible microstates or configuration of the system

In the given case, W = 36. Now, we will put the given values into the above formula as follows.

                  s = k ln W

                    = 1.38 \times 10^{-23} ln (36)        

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Thus, we can conclude that the entropy of this system is 4.945 \times 10^{-23} J/K.

4 0
4 years ago
A sample of oxygen gas occupies a volume of 5.0L at 90kPa pressure. What volume will it occupy at 145kPa?
Burka [1]

Answer:

<h3>The answer is option A</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{5 \times 90000}{145000}  =  \frac{450000}{145000}  =  \frac{450}{145}  \\  = 3.103448...

We have the final answer as

<h3>3.10 L</h3>

Hope this helps you

7 0
3 years ago
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