Answer:
A. K = 0.546 eV
B. cooper and iron will not emit electrons
Explanation:
A. This is a problem about photoelectric effect. Then you have the following equation:
(1)
K: kinetic energy of the ejected electron
Ф: Work function of the metal = 2.48eV
h: Planck constant = 4.136*10^{-15} eV.s
λ: wavelength of light = 410nm - 750nm
c: speed of light = 3*10^8 m/s
As you can see in the equation (1), higher the wavelength, lower the kinetic energy. Then, the maximum kinetic energy is obtained with the lower wavelength (410nm). Thus, you replace the values of all variables :
![K=(4.136*10^{-15}eV)\frac{3*10^8m/s}{410*10^{-9}m}-2.48eV\\\\K=0.546eV](https://tex.z-dn.net/?f=K%3D%284.136%2A10%5E%7B-15%7DeV%29%5Cfrac%7B3%2A10%5E8m%2Fs%7D%7B410%2A10%5E%7B-9%7Dm%7D-2.48eV%5C%5C%5C%5CK%3D0.546eV)
B. First you calculate the energy of the photon with wavelengths of 410nm and 750nm
![E_1=(4.136*10^{-15}eV)\frac{3*10^{8}m/s}{410*10^{-9}m}=3.02eV\\\\E_2=(4.13610^{-15}eV)\frac{3*10^{8}m/s}{750*10^{-9}m}=1.6544eV](https://tex.z-dn.net/?f=E_1%3D%284.136%2A10%5E%7B-15%7DeV%29%5Cfrac%7B3%2A10%5E%7B8%7Dm%2Fs%7D%7B410%2A10%5E%7B-9%7Dm%7D%3D3.02eV%5C%5C%5C%5CE_2%3D%284.13610%5E%7B-15%7DeV%29%5Cfrac%7B3%2A10%5E%7B8%7Dm%2Fs%7D%7B750%2A10%5E%7B-9%7Dm%7D%3D1.6544eV)
You compare the energies E1 and E2 with the work functions of the metals and you can conclude:
sodium = 2.3eV < E1
cesium = 2.1 eV < E1
cooper = 4.7eV > E1 (this metal will not emit electrons)
iron = 4.5eV > E1 (this metal will not emit electrons)
by angular momentum conservation we will have
angular momentum of child + angular momentum of merry go round = 0
angular momentum of child = mvR
m = mass of child
R = radius of child
v = speed = 2 m/s
now let's say moment of inertia of merry go round is I
so we will have
![m*2*R + Iw = 0](https://tex.z-dn.net/?f=%20m%2A2%2AR%20%2B%20Iw%20%3D%200)
![w = -\frac{2mR}{I}](https://tex.z-dn.net/?f=w%20%3D%20-%5Cfrac%7B2mR%7D%7BI%7D)
so merry go round will turn in opposite direction with above speed
Answer:
1.28 m
Explanation:
Generally, pressure of fluid is given by
where g is acceleration due to gravity, h is the height and
is the density
Considering that the pressure for mercury is same as for blood only that the height and density of fluid are different then
Since g is constant, then
Making
the subject of the formula then
![h_b=\frac {\rho_m h_m}{\rho_b}](https://tex.z-dn.net/?f=h_b%3D%5Cfrac%20%7B%5Crho_m%20h_m%7D%7B%5Crho_b%7D)
Where subscripts m and b denote mercury and blood respectively
Assuming density of blood is 1060 Kg/m3, density of mercury as 13600 Kg/m3 and substituting height of mercury for 0.1 m then
![h_b=\frac {13600*0.1}{1060}=1.283018868 m \approx 1.28 m](https://tex.z-dn.net/?f=h_b%3D%5Cfrac%20%7B13600%2A0.1%7D%7B1060%7D%3D1.283018868%20%20m%20%5Capprox%201.28%20m)
radio waves bc they have the longest wave lenthgs in a magnetic spectrum