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anastassius [24]
3 years ago
7

A 900 kg car travelling at 12 m/s due east collides with a 600 kg car travelling at 24 m/s due north. As a result of the collisi

on, the two cars lock together and move in what final direction?
45.0° N of E

53.1° N of E

63.3° N of E

69.5° N of E
Physics
1 answer:
katrin [286]3 years ago
8 0

Calculate force of each car:

P1 = 900 kg x 12m/s = 10,800

P2= 600 x 24 = 14,400

Degree of travel = arctan(14,300/10800)

Degree of travel = 53.1 N of E

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Hello!

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Answer:

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I found the answer for you if u need any help ask anytime!

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