All categories

2 years ago

Predict the neutral organic product of the reaction of cycloheptene with water and sulfuric acid.

Chemistry

1 answer:

Leokris [45]2 years ago

7 0

The term hydration of an alkene is defined as the addition of water across a double bond.

<h3>What is hydration?</h3>

The term hydration of an alkene is defined as the addition of water across a double bond. The process of hydration always yields an alcohol as -OH is aded to one of the carbon atoms in the doube bond.

The reaction commences with the attack of the -OH group by water and is completed by a proton from acid. The neutral organic product of the reaction of cycloheptene with water and sulfuric acid is shown in the image attached.

Learn more about hydration: brainly.com/question/12034258

You might be interested in

What conducts better, metal or nometal? <br> why?

Rama09 [41]

Metal because it’s more stronger

8 0

2 years ago

55 points take the or whatever but Im getting head on my 15th bday on march 26th gonna be great also help me Two or more substan

Kipish [7]

Mixture is the answer.

3 0

2 years ago

The side chains of amino acids may contain..

salantis [7]

The correct answer is d)all of above

examples for a are tyrosine for b lysine and for c isoleucine

6 0

3 years ago

Read 2 more answers

August kekule described the various ring structures of the carbon compound benzene. What type of chemist would he be considered

Andreyy89

B. He would be considered an Organic Chemist since Organic Chemistry is the study of Carbon and its compounds.

3 0

3 years ago

Read 2 more answers

). The molar mass of an organic acid, a compound composed of carbon, hydrogen, and oxygen, is 194.14 g/mol. Combustion of a 1.50

Nikitich [7]

Answer:

The empirical formula is C₆H₁₀O₇.

Step-by-step explanation:

1. Calculate the masses of C, H, and O from the masses given.

Mass of C = 2.0402 g CO₂ × (12.01 g C/44.01 g CO₂) = 0.5568 g C

Mass of H = 0.6955 g H₂O × (2.016 H/18.02 g H₂O) = 0.077 81 g H

Mass of O = Mass of compound - Mass of C - Mass of H = (1.500 – 0.5568 – 0.077 81) g = 0.8654 g O

=====

2. Convert these masses to moles.

Moles C = 0.5568 × 1/12.01 = 0.046 36

Moles H = 0.077 81 × 1/1.008 = 0.077 19

Moles O = 0.8654 × 1/16.00 = 0.054 09

=====

3. Find the molar ratios.

Moles C = 0.046 36/0.046 36 = 1

Moles H = 0.077 19/0.046 36 = 1.665

Moles O = 0.054 09/0.046 36 = 1.167

======

4. Multiply the ratios by a number to make them close to integers

C = 1 × 6 = 6

H = 1.665 × 6 = 9.991

O = 1.167 × 6 = 7.001

=====

5. Round the ratios to integers

C:H:O =6:10:7

=====

6. Write the empirical formula

The empirical formula is C₆H₁₀O₇.

=======

7. Calculate the empirical formula mass

C₆H₁₀O₇ = 6×12.01 + 10×1.008 + 7×16.00

C₆H₁₀O₇ = 72.01 + 10.08+ 112.0

C₆H₁₀O₇ = 194.09

=====

8. Divide the molecular mass by the empirical formula mass.

MM/EFM = 194.14/194.09 = 1.000 ≈ 1

=====

9. Determine the molecular formula

MF = (EF)ₙ = (C₆H₁₀O₇)₁ = C₆H₁₀O₇

7 0

3 years ago