Answer:
Electrical power is the product of voltage times current.
Answer:
quartz and olivine
Explanation:
According to my research on studies made by different geologists on Bowen's reaction series, it is known that crystal settling should result in the magma being separated in lower layers rich in the early-formed quartz and olivine minerals.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Explanation:
Entropy is defined as the degree of randomness present in a substance. Therefore, more is the irregularity present in a compound more will be its molar entropy.
Hence, decreasing order to molar entropy in state of matter is as follows.
Gases > Liquids > Solids
- In the first pair, we are given
or
. Since, molar entropy of liquids is less than the molar entropy of gases.
Hence,
will have larger molar entropy as compared to
.
- In the second pair, we are given Fe(s) or Ni(s). More is the molar mass of a compound more will its molar entropy. Molar mass of Fe is 55.84 g/mol and molar mass of Ni is 58.69 g/mol.
Hence, molar entropy of Ni(s) is more than the molar entropy of Fe(s).
- In the third pair, we are given
or
. As both the given species are gaseous in nature. So, more is the molar mass of specie more will be its molar entropy.
Molar mass of
is 30.07 g/mol and molar mass of
is 28.05 g/mol. Therefore, molar entropy of
is more than the molar entropy of
.
- In the fourth pair, we are given
or
. Molar mass of
is 153.82 g/mol and molar mass of
is 16.04 g/mol.
Therefore, molar entropy of
is more than the molar entropy of
.
- In the fifth pair, we are given HgO(s) or MgO(s). Molar mass of HgO is 216.59 g/mol and molar mass of MgO is 40.30 g/mol.
Hence, molar entropy of HgO(s) is more than the molar entropy of MgO.
- In the fifth pair, we are given NaCl(aq) or
. Molar mass of NaCl 58.44 g/mol and molar mass of
is 95.21 g/mol.
Hence, the molar entropy of
is more than the molar entropy of NaCl(aq).
Answer:
Here's what I get
Explanation:
The ionization energy (I) is the energy required to remove an electron from an atom in the gaseous phase.
You can remove electrons in succession and measure the energies required as I₁, I₂, I₃, etc.
Thus, the removal of two electrons from Cu gives you Cu²⁺.
I found the ionization energies of Cu and used them to create those of Cu²⁺ (see table and graph below).
The electron configuration of Cu²⁺ is
Cu²⁺: 1s² 2s²2p⁶ 3s²3p⁶ 3d⁹
You can remove the nine 3d electrons and then there is a sudden jump from I₉ to I₁₀ as you break into the filled [Ar] configuration.
Similarly, there is big jump from I₁₇ to I₁₈ as you break into the filled [Ne] configuration.