The distance of the canoeist from the dock is equal to length of the canoe, L.
<h3>
Conservation of linear momentum</h3>
The principle of conservation of linear momentum states that the total momentum of an isolated system is always conserved.
v(m₁ + m₂) = m₁v₁ + m₂v₂
where;
v is the velocity of the canoeist and the canoe when they are together
- u₁ is the velocity of the canoe
- u₂ velocity of the canoeist
- m₁ mass of the canoe
- m₂ mass of the canoeist
<h3>Distance traveled by the canoeist</h3>
The distance traveled by the canoeist from the back of the canoe to the front of the canoe is equal to the length of the canoe.
Thus, the distance of the canoeist from the dock is equal to length of the canoe, L.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer: coefficient of static friction
= 0.31
Explanation: Since they negotiate the curve without skidding, the frictional force (F1) equals the centripetal force (F2).
F1= uN
F2 = M*(v²/r)
M is the combined mass 450kg
V is the velocity 18m/s
r is the radius 106m
N is the normal reaction 4410N
u is the coefficient of static friction
Making u subject of the formula we have that,
u = {450*(18²/106)} /4410
=1375.47/4410
=0.31
NOTE: coefficient of friction is dimensionless. It as no Unit.
Answer:
160000000 kg.
Explanation:
p=mv
p=1.6x10^9
v=10m/s
rearrange and substitute:
(1.6x10^9)=m(10)
m=(1.6x10^9)/10
m= 1.6x10^8 kg.
1. a=Δv/Δt=(v-vo)/t=(0-25)/5=-25/5=-5 m/s²
The "-" sign shows us that the car has a slow motion
2.a=Δv/Δt=(v-vo)/t=(10-0)/4=10/4=2,5 m/s²
3.they do not have acceleration because they go at constant speed
The force of the push and acceleration of the cart are related such as The unbalanced push causes the cart to accelerate.
