Answer:
The answer to your question is: vf = 30 m/s
Explanation:
Data
vo = 15 m/s
a = 3.0 m/s²
t = 5 s
vf = ?
Formula
vf = vo + at
Substitution
vf = 15 + (3)(5)
vf = 15 + 15
vf = 30 m/s
Answer: 17.59 Hz and 4.87 m
Explanation:
The fundamental frequency of the sound from an open-open pipe is given as
f= 
where v= 343 m/s
L= 32 feet= 
= 9.75 m
So,
f= 
= 17.59 Hz
The length of open-closed tube is related to frequency by formula
f= 
or L=
L= 
L= 4.87 m
Answer:
Explanation:
a ) Let the distance required in former case be d₁ .
initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 7.00 m /s²
v² = u² - 2 a s
0 = 30² - 2 x 7 x d₁
d₁ = 64.28 m
b) initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 5.00 m /s²
v² = u² - 2 a s
0 = 30² - 2 x 5 x d₂
d₂ = 90 m
c)
t = .5 s
s₁ = ut - .5 at²
= 30 x .5 - .5 x 7 x .5²
= 15 - .875
= 14.125 m
t = .5 s
s₂ = ut - .5 at²
= 30 x .5 - .5 x 5 x .5²
= 15 - .625
= 14.375 m
Answer:
coefficient of friction =0.268
magnitude of force P=289.78N
Explanation:
The coefficient of friction is obtained by mgsinФ/mgcosФ=tanФ=tan15=0.268
force P is horizontal as stated in the question, horizontal component of P=mgcosФ=30*10*cos15=289.78
Answer:
The answer is "
"
Explanation:
Calculating the mass flow rate of fluid:
Calculating the amount of heat transfer.
Calculating the required value for heat flux:
