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sleet_krkn [62]
2 years ago
15

When a -3.72*10^-4 C charge

Physics
1 answer:
nexus9112 [7]2 years ago
8 0

The potential difference between A and B is -586.02 V, when the potential energy increases by 0.218 J.

<h3>Potential difference between A and B</h3>

The potential difference between A and B is determined as follows;

W = qΔV

where;

  • W is the work done
  • q is the charge
  • ΔV is the potential difference

The potential difference between A and B is calculated as follows;

ΔV = W/q            

(U = -W) and U = 0.218 J

ΔV = -0.218/(3.72 x 10⁻⁴)

ΔV = -586.02 V

Thus, the potential difference between A and B is -586.02 V, when the potential energy increases by 0.218 J.

Learn more about potential difference here: brainly.com/question/25923373

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