Answer:
Option C. 251 kJ
Explanation:
The activation energy (Ea) of a given reaction is the minimum energy that must be overcomed for reactant to proceed to product.
The activation energy (Ea) can be obtained from an energy profile diagram by simply calculating the difference between the energy of the activation complex (i.e the peak) and the energy of the reactant.
Thus, we can obtain the activation energy for the reaction above as follow:
Activation complex = 332.6 kJ
Energy of reactant = 81.6 kJ
Activation energy =?
Activation energy = Activation complex – Energy of reactant
Activation energy = 332.6 – 81.6
Activation energy = 251 kJ
Therefore, the activation energy of the reaction is 251 kJ
Answer:
A great example would be a fish, it needs the water to breathe just like how we humans need oxygen. If a fish were to get out of the water it would die.
Explanation:
Answer:
Standard reduction potential is an intensive property---- True
Reduction takes place at the anode ----- False
The half reaction with the lower standard reduction potential will be at the cathode in a galvanic cell ------false
The half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell ------ True
Explanation:
An intensive property is a property of a substance which is inherent in it and part of its nature. It does not depend on the amount of substance present in the substance. Standard reduction potential is an intensive property.
In a galvanic cell, oxidation takes place at the anode and reduction takes place at the cathode. At the anode, the electrode potential is more negative (an oxidation) while at the cathode the reduction potential is less negative (a reduction).
Answer:
Specififc rotation [∝] = 0.5° mL/g.dm
Explanation:
Given that:
mass = 400 mg
volume = 10 mL
For a solution,
The Concentration = mass/volume
Concentration = 400/10
Concentration = 40 g/mL
The path length l = 20 cm = 2 dm
Observed rotation [∝] = + 40°
Specififc rotation [∝] = ∝/l × c
where;
l = path length
c = concentration
Specififc rotation [∝] = (40 / 2 × 40)
Specififc rotation [∝] = 0.5° mL/g.dm
