Balanced equation: 10 CaCo3 + 20 HCl = 10 CaCl2 + H20 + 15 Co2
When mass Ti = density * volume
and when moles Ti = mass Ti/molar mass Ti
∴ Volume = 2.86 x 10^23 atom * ( 1 mol Ti / 6.022 x 10^23) * (47.867 g Ti / 1 mol Ti) *(1Cm3 / 4.5 g Ti )
= 5.05 Cm^3
when we assume that the sample of Ti is a cube:
and we assume the length = X
∴ V = X^3
∴X^3 = 5.05
∴X = ∛5.05
= 1.7 Cm
4 NH₃ + 3O₂ --> 2N₂ + 6H₂O
First, make sure that this is a balanced equation.
There are 4 moles of nitrogen on the left side, and 4 moles of nitrogen on the right side.
There are 12 moles of hydrogen on the left side, and 12 moles of hydrogen on the right side.
There are 6 moles of oxygen on the left side, and 6 moles of oxygen on the right side.
The equation is therefore balanced, and we may proceed.
a) the mole ratio for NH₃ to N₂ is 4 to 2, which can be simplified to 2:1 or 2/1.
b) the mole ratio for H₂O to O₂ is 6 to 3, which can be simplified to 2:1 or 2/1.
Are you looking for the definition or answer? Since nomenclature is just definition by name or giving a specific name; the overall answer should be Carbon Dioxide.
