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Phantasy [73]
3 years ago
5

How much energy is gained when a 10.0g sample of liquid water increases in temperature from 13°C to 18°C?

Chemistry
2 answers:
crimeas [40]3 years ago
5 0

Answer:

Your answer is 209 J.

Explanation:

First find △T by subtraction of two temperatures.

△T = 18°C - 13 °C

= 5°C.

Q=mc△t

where,

m= mass.

c = Specific Heat .

t = temperature.

As, Specific Heat capacity of water is 4.18 J/g°C

= 10 × 4.18× 5

= 209 Joules.

Ivan3 years ago
4 0

When a 10g sample of liquid water increases in temperature from 13°C to 18°C, then the amount of gained energy is 209 joules.

<h3>How do we calculate gained energy?</h3>

The amount of energy which is gained by any sample will be calculated as:

Q = mcΔT, where

Q = gained energy

m = mass of sample = 10g

c = specific heat of water = 4.18 J/g°C

ΔT = change in temperature = 18 - 13 = 5°C

On putting values we get

Q = (10)(4.18)(5)

Q = 209 Joules

Hence required amount of energy is 209 joules.

To know more about gained energy, visit the below link:

brainly.com/question/21704399

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