Answer:
The correct/closest option is b
Explanation:
Restriction enzymes are enzymes (endonucleases) that cut short DNA strands at specific sites. Hence, each restriction enzyme has it's own specific site (between two bases) it cuts at. There are two types of end that can be produced by this cut; the blunt end and the sticky end.
A restriction enzyme recognizes (palindromic sequence) and cut in it's own specific end.
For example, if a restriction enzyme cuts between a guanine (G) and an adenine (A), and it cuts a palindromic double stranded DNA in the manner below, it produces a sticky end.
G║AATTC
CTTAA║G
And if a restriction enzyme cuts between guanine (G) and cytosine (C) in the manner below, it produces a blunt end.
GGG║CCC
CCC║GGG
Hence, from the question, restriction enzymes (although chosen by the scientist based on desired sequence to be cut) recognize the sticky or blunt ends itself.
1 micro gram of Strontium-90 has an activity of
0.0000053 terabecquerels (TBq),
Explanation:
Given information denotes that .,one gram of Strontium-90 has an activity of 5.3 terabecquerels (TBq)
the activity of 1 micro gram is
1 gram = 1,000,000 micro gram has activities of 5.3 terabecquerels
therefore 1 micro gram has the activity of (5.3 ÷ 1,000,000 = 0.0000053 )
= 
Hence ., 1 micro gram of Strontium-90 has an activity of
0.0000053 terabecquerels (TBq),
Answer:
One of the differences is that civil engineering focuses on design elements while structural engineering is more concern on inspecting the materials used for construction. The structural engineers are the one who are supposed to ensure that the materials used for construction can support the design of the structure.
Explanation:
Answer:
c = 18.0569 mm
Explanation:
Strategy
We will find required diameter based on angle of twist and based on shearing stress. The larger value will govern.
Given Data
Applied Torque
T = 750 N.m
Length of shaft
L = 1.2 m
Modulus of Rigidity
G = 77.2 GPa
Allowable Stress
г = 90 MPa
Maximum Angle of twist
∅=4°
∅=4*
/180
∅=69.813 *10^-3 rad
Required Diameter based on angle of twist
∅=TL/GJ
∅=TL/G*
/2*c^4
∅=2TL/G*
*c^4
c=
∅
c=18.0869 *10^-3 rad
Required Diameter based on shearing stress
г = T/J*c
г = [T/(J*
/2*c^4)]*c
г =[2T/(J*
*c^4)]*c
c=17.441*10^-3 rad
Minimum Radius Required
We will use larger of the two values
c= 18.0569 x 10^-3 m
c = 18.0569 mm