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mr Goodwill [35]
2 years ago
15

Bonding with intermolecular forces:

Chemistry
1 answer:
Kay [80]2 years ago
7 0

Answer:

1. yes

2. yes

3. no

sorry if I am wrong but hope this helps

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The answer you would be looking for is option A because all of the other options are either false, or beneficial to us, and i took the test. Thanks

Explanation:

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A student was given a piece of metal with a mass of 85.0 g. She placed it
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Compute the values of the diffusion coefficients for the interdiffusion of carbon in both α-iron (BCC) and γ-iron (FCC) at 900°C
bogdanovich [222]

Answer:

α-iron (BCC) has faster diffusion rate because of lower values in activation energy and pre-exponential value.

Explanation:

Taking each parameters or data at a time, we can determine the values/a constant for each parameters in the diffusion coefficient equation.

For α-iron (BCC), the diffusion coefficient = pre-exponential value,Ao × e^( -Activation energy,AE)/gas constant,R × Temperature.

Converting the given Temperature, that is 900°C to Kelvin which is equals to 1173.15K.

For α-iron (BCC), the pre-exponential value, Ao = 1.1 × 10^-6, and the activation energy, AE = 87400.

Thus, we have that the diffusion coefficient = 1.1 × 10^-6 × e(-87400)/1173.15 × 8.31.

Diffusion coefficient for α-iron (BCC) = 1.41 × 10^-10 m^2/s.

Also, For the γ-iron (FCC), the pre-exponential value, Ao = 2.3 × 10^-5 and the activation energy, AE = 148,00.

From these values we can see that both the exponential value, Ao and the activation energy for γ-iron (FCC) are higher than that of α-iron (BCC).

Thus, the diffusion coefficient for the γ-iron (FCC) = 2.3 × 10^-5 × e ^-(14800)/8.31 × 1173.15.

Then, the diffusion coefficient for the γ-iron (FCC) = 5.87 × 10^-12 m2/s.

Therefore, there will be faster diffusion in α-iron (BCC) because of lower activation energy and vice versa.

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The third option, 2,2,1,2
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Write the overall equation for the reaction occurring in lithium battery?
lisov135 [29]

Answer:

In the chemical industry, lithium-based batteries are working most efficiently and replacing nickel-cadmium batteries. To study a redox reaction in a lithium battery let's take the example of Lithium Cobalt Oxide(LiCoO2).

Following is the overall reaction taking place in Lithium Cobalt Oxide battery. Reduction and oxidation takes place at Cathode and Anode respectively. that is why it is called a redox reaction.

Reaction at cathode:

Cathode: CoO2+Li+e−→ LiCoO2 (Reduction)

Reaction at Anode:

Anode: LiC6→ C6+Li++e− (Oxidation)

Overall reaction:  

LiC6 + CoO2→ C6 + LiCoO2

6 0
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