As additional resistors are connected in series to a constant voltage source, how is the power supplied by the source affected?

Physics

2 answers:

Furkat [3]3 years ago

7 0

Answer:

(D) The power supplied by the source decreases.

Explanation:

If additional resistors are connected in series, then the total resistance of the circuit is increased. By the Ohm’s Law, V = iR, the current decreases.

The power supplied by the source is P = i*i*R = i*(i*R). The term in the parenthesis is the voltage of the circuit and is constant. The ‘i’ outside decreases, therefore the power supplied by the source decreases.

stepan [7]3 years ago

6 0

Answer:

(D) the power supplied by the source decreases

Explanation:

V = IR

- VOLTAGE remains same, increase in resistance causes decrease in current flowing.

P = $\frac{V^{2} }{R}$

- increase in denominator (R) decreases the power.

You might be interested in

Consider a coin which is tossed straight up into the air. After it is released it moves upward, reaches its highest point and fa

avanturin [10]

Answer:

GRAVITATIONAL FORCE

Explanation:

We may have noticed that a body thrown upward in air falls back down again after attaining a particular height. The object was able to fall down back due to the effect of gravity acting on it. If there are no force of gravity acting on the body, the body will not fall back but rather disappears into the thin air.

A coin tossed upward in the air which falls back down when released is therefore under the influence of gravity i.e GRAVITATIONAL FORCE while it moves upward after it is released

3 0

3 years ago

A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate

diamong [38]

To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

$\Delta S = \frac{Q}{T}$