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krok68 [10]
3 years ago
6

As additional resistors are connected in series to a constant voltage source, how is the power supplied by the source affected?

Physics
2 answers:
Furkat [3]3 years ago
7 0

Answer:

(D) The power supplied by the source decreases.

Explanation:

If additional resistors are connected in series, then the total resistance of the circuit is increased. By the Ohm’s Law, V = iR, the current decreases.

The power supplied by the source is P = i*i*R = i*(i*R). The term in the parenthesis is the voltage of the circuit and is constant. The ‘i’ outside decreases, therefore the power supplied by the source decreases.

stepan [7]3 years ago
6 0

Answer:

(D) the power supplied by the source decreases

Explanation:

V = IR

- VOLTAGE remains same, increase in resistance causes decrease in current flowing.

P = \frac{V^{2} }{R}

- increase in denominator (R) decreases the power.

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Explain what characterises a sound as noise or music​
natta225 [31]

Explanation:

Noise is sound with a continuous structure. Music is composed of sounds with a fundamental frequency and overtones. Noise is composed of sounds with frequencies that range continuously in value from as low as you can hear to as high as you can hear — not necessarily at equal intensity, however.

7 0
2 years ago
A thermometer initially reading 212F is placed in a room where the temperature is 70F. After 2 minutes the thermometer reads 125
frez [133]

Answer:

91.3°F

Explanation:

Let T be the temperature of the thermometer at any time

T∞ be the temperature of the room = 70°F

T₀ be the initial temperature of the thermometer = 212°F

And m, c, h are all constants from the cooling law relation

From Newton's law of cooling

Rate of Heat loss by the cake = Rate of Heat gain by the environment

- mc (d/dt)(T - T∞) = h (T - T∞)

(d/dt) (T - T∞) = dT/dt (Because T∞ is a constant)

dT/dt = (-h/mc) (T - T∞)

Let (h/mc) be k

dT/(T - T∞) = -kdt

Integrating the left hand side from T₀ to T and the right hand side from 0 to t

In [(T - T∞)/(T₀ - T∞)] = -kt

(T - T∞)/(T₀ - T∞) = e⁻ᵏᵗ

(T - T∞) = (T₀ - T∞)e⁻ᵏᵗ

Inserting the known variables

(T - 70) = (212 - 70)e⁻ᵏᵗ

(T - 70) = 142 e⁻ᵏᵗ

At t = 2 minute, T = 125°F

125 - 70 = 142 e⁻ᵏᵗ

55/142 = e⁻ᵏᵗ

- kt = In (55/142) = In (0.3873)

- k(2) = - 0.9485

k = 0.4742 /min

At time t = 4 mins

kt = 0.4742 × 4 = 1.897

(T - 70) = 142 e⁻ᵏᵗ

e^(-1.897) = 0.15

T - 70 = 142 × 0.15 = 21.3

T = 91.3°F

7 0
3 years ago
A force of 6.00 N acts in the positive direction on a 3.00 kg object, originally traveling at +15.0 m/s, for 10.0 s. (a) What is
frozen [14]

Answer:

60 kg m/s

Explanation:

Let a\;\; m/s^2 be the acceleration of the object.

As the acceleration of the object is constant, so

a=\frac {v-u}{t}\cdots(i)

Given that applied force, F=6.00 N,

From Newton's second law, we have

F= m\times a,

\Rightarrow F=\frac {m(v-u)}{t} [from equation (i)]

\Rightarrow Ft=m(v-u)

\Rightarrow Ft=mv-mu

\Rightarrow mv-mu=6\times 10 [given that time, t=10 s and F=6 N]

\Rightarrow mv-mu=60 kg \;m/s

Here mv is the final momentum of the object and mu is the initial momentum of the object.

So, the change in the momentum of the object is mv-mu.

Hence, the change in the momentum of the object is 60 kg m/s.

6 0
3 years ago
Please answer correctly<br>Will give the brainliest!​
Oksi-84 [34.3K]

In the first case:

when we heat any gas, the Kinetic Energy of the molecules increases, making it collide more frequently with the surface, increasing the pressure

more collisions with the surface means more force applied on it, which would push the piston harder than before, moving it outwards.

In the second case:

since the molecules inside the beaker have no way to escape, they would keep compressing the more you push the beaker downwards.

since there is the same number of molecules and lesser volume to cover, the molecules will start colliding with the surfaces more frequently, which would resist the downward force.

<em>another way to think about it is to imagine yourself where the trapped air is. you would be happy when the room is spacious but if the wall starts moving towards you, you would resist the change by your body because you need space to exist. making it harder for the wall to move.</em>

<em>pushing the beaker downwards will keep getting harder and harder the more you push until you reach a point where the molecules will be completely compact. applying even more force forces the molecules to enter water, removing the air that was resisting it all and making you able to get the beaker in water.</em>

Third case:

just like in the first case, the heated air will apply force on the surface, including the cork. which would pop off when enough force is applied.

3 0
3 years ago
A stone initially moving at 8.0 m/s on a level surface comes to rest due to friction after it travels 11 m. What is the coeffici
Ivenika [448]

Answer:

Coefficient of friction will be 0.296

Explanation:

We have given initial speed of the stone u = 8 m /sec

It comes to rest so final speed v = 0 m /sec

Distance traveled before coming to rest s = 11 m

According to third equation of motion

v^2=u^2+2as

So 0^2=8^2+2\times a\times 11

a=\frac{-64}{22}=-2.90m/sec^2

Acceleration due to gravity g=9.8m/sec^2

We know that acceleration is given by

a=\mu g

So 2.90=9.8\times \mu \\

\mu =\frac{2.9}{9.8}=0.296

So coefficient of friction will be 0.296

3 0
3 years ago
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