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cestrela7 [59]
3 years ago
7

15. You have a solution of .835mol of NaCl in 2.5L of solution, what is the molarity?

Chemistry
1 answer:
Viktor [21]3 years ago
5 0

Answer: 0.334mol/L

Explanation:

M=\frac{mol}{L}

M=\frac{0.835mol}{2.5L} \\M=0.334mol/L

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Answer:

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Thus the correct answer is the third option.

8 0
3 years ago
Which layer is the oldest layer? How can you tell? ​
Neporo4naja [7]

Answer:

The principle of superposition states that the oldest rock units are at rock bottom , and therefore the youngest are at the highest . Based on this, layer C is oldest, followed by B and A. So the full sequence of events is as follows: Layer C formed.

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6 0
3 years ago
Read 2 more answers
The equilibrium constant Kp for the reaction (CH3),CCI (g) = (CH3),C=CH, (g) + HCl (g) is 3.45 at 500. K. (5.00 x 10K) Calculate
Karolina [17]

<u>Answer:</u> The value of K_p for the reaction is 6.32 and concentrations of (CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl is 0.094 M, 0.094 M and 0.106 M respectively.

<u>Explanation:</u>

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

where,

K_p = equilibrium constant in terms of partial pressure = 3.45

K_c = equilibrium constant in terms of concentration = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 500 K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-1=1

Putting values in above equation, we get:

3.45=K_c\times (0.0821\times 500)^{1}\\\\K_c=\frac{3.45}{0.0821\times 500}=0.084

The equation used to calculate concentration of a solution is:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}

Initial moles of (CH_3)_3CCl(g) = 1.00 mol

Volume of the flask = 5.00 L

So, \text{Concentration of }(CH_3)_3CCl=\frac{1.00mol}{5.00L}=0.2M

For the given chemical reaction:

                (CH_3)_3CCl(g)\rightarrow (CH_3)_2C=CH(g)+HCl(g)

Initial:               0.2                    -                        -

At Eqllm:          0.2 - x               x                       x

The expression of K_c for above reaction follows:

K_c=\frac{[(CH_3)_2C=CH]\times [HCl]}{[(CH_3)_3CCl]}

Putting values in above equation, we get:

0.084=\frac{x\times x}{0.2-x}\\\\x^2+0.084x-0.0168=0\\\\x=0.094,-0.178

Negative value of 'x' is neglected because initial concentration cannot be more than the given concentration

Calculating the concentration of reactants and products:

[(CH_3)_2C=CH]=x=0.094M

[HCl]=x=0.094M

[(CH_3)_3CCl]=(0.2-x)=(0.2-0.094)=0.106M

Hence, the value of K_p for the reaction is 6.32 and concentrations of (CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl is 0.094 M, 0.094 M and 0.106 M respectively.

8 0
3 years ago
If a sodium ion has 11 protons, 12 neutrons, and 11 electrons, what is the atomic mass of the atom?
iragen [17]

Answer:

23

Explanation:

we do not care about electrons, so 11 + 12 = 23

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3 years ago
Diferences between a Human and a Lion
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Lions walk on 4 legs, humans walk on 2. female lions live in groups but are taken over by groups of male lions from time to time, human adults tend to live alone or in pairs with their offspring. Humans can talk and lions cannot. lions have manes around the face.
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3 years ago
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