Is this true or false?
1 answer:
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Answer:
- <u><em>Option D. There will be a shift toward the reactants.</em></u>
Explanation:
The reaction is:
The application of LeChatelier's principle leads to consider the <em>heat</em> as a <em>reactant</em> or a product depending on if it is on the left side or the right side.
In this reaction, the <em>heat</em> is on the left side, thus it must be considered a <em>reactant</em>.
Decreasing the temperature is equivalent to remove or consume heat. Thus, the reaction must shif to the left to compensate that reduction of heat. That is the reverse reaction shall be favored.
In conclusion, <em>there will be a shift toward the reactants.</em>
The percent of water in the hydrated salt will be 55.08 %
<h3>What is mass?</h3>Mass is a numerical measure of quantity, which is a basic feature of all matter. The kilogram is the international system of units of mass.
Given data;
Mass of crucible, cover, and contents before heating = 23.4 g.
Mass of empty crucible and cover = 18.82 g.
Mass of crucible, cover, and contents after heating to constant mass = 20.94 g.
⇒Mass of hydrated salt used = Mass of the crucible, cover, and contents before heating - Mass of the empty crucible and cover
⇒Mass of hydrated salt used = = 23.54 g – 18.82 g
⇒Mass of hydrated salt used = = 4.72 g
⇒Mass of dehydrated salt after heating = Mass of the crucible, cover, and contents after heating to constant mass-Mass of the empty crucible and cover
⇒Mass of dehydrated salt after heating = 20.94 g – 18.82 g
⇒Mass of dehydrated salt after heating = 2.12 g
⇒ Mass of water liberated from salt = Mass of hydrated salt used - Mass of dehydrated salt after heating
⇒ Mass of water liberated from salt = 4.72 g – 2.12 g
⇒ Mass of water liberated from salt = 2.60 g
Water % in the hydrated salt is found as;
% water =(mass of water/ mass of hydrated salt)× 100
% water =(2.60/4.72) × 100
% water =55.08 %
Hence the percent of water in the hydrated salt will be 55.08 %
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