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2 years ago

The Second Law of Thermodynamics states that: Select one:

Chemistry

1 answer:

lianna [129]2 years ago

8 0

Answer:

In the total entropy of an isolated system, the thermal energy per unit temperature that is unavailable for doing useful work can never decrease.

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When a solution of AgNO3 is mixed with a solution of NaBr (multiple options could be correct):

alex41 [277]

Answer:

After a few minutes pass, the concentration of Ag+ and Br- will be lower than when the two solutions were first mixed.

AgBr precipitate will spontaneously form.

Explanation:

After the net ionic equation AgBr forms

7 0

3 years ago

Calculate gram formula mass of LiCl(s)

Nadya [2.5K]

Answer:

The answer is 42, 39 grams of LiCl

Explanation:

We calculate the weight of 1 mol of LiCl, from the atomic weights of each element obtained from the periodic table:

Weight 1 mol LiCl= Weight Li + Weight Cl =6,94 g+ 35, 45 g= 42, 39grams

5 0

3 years ago

What problems might happen if an unnecessary hurricane warning was issues

deff fn [24]

People would rush to the store to buy supplies and there might not be enough for the "last minute noticed" people

4 0

3 years ago

Jacob takes 7 classes, each 50.00 minutes long every day for the 5 day school week. How many hours per week does he spend in cla

Zina [86]

Answer: He spends 29.17 hours per week

Explanation:

1 class = 50mins

7 classes = 7 x 50mins = 350mins

For 5 days in a week, we have

5 x 350mins = 1750mins

Converting to hours, we have

1750 /60 = 29.17 hours

5 0

3 years ago

The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd

kenny6666 [7]

Answer:

The answer is " $= 0.078 \ kg \ H_2$ ".

Explanation:

calculating the moles in $CH_4 =\frac{PV}{RT}$

$=\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol$

Eqution:

$CH_4 +H_2O \to 3H_2+ CO \ (g)$

Calculating the amount of $H_2$ produced:

$= 12.9 \ mol CH_4 \times \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2$

So, the amount of dihydrogen produced = $0.078 \frac{kg}{s}$

5 0

3 years ago