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The number of moles of NO₂ that would be produced from 3.9 mol of O₂ in the reaction is 5.13 moles NO2.
<h3>What is nitrogen?</h3>
Nitrogen is a monatomic gas. It is the most abundant gas present in the environment.
4.5 mol O2 x (2 mol NO2/ 1 mol O2) = 9 mol NO2
For 57% yield of the reaction
9 mol NO2 x 0.57 = 5.13 moles NO2.
Thus, the number of moles of NO₂ is 5.13 moles.
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Answer : The time passed in days is 28.6 days.
Explanation :
Half-life = 14.3 days
First we have to calculate the rate constant, we use the formula :
Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant =
t = time passed by the sample = ?
a = let initial amount of the reactant = 100 g
a - x = amount left after decay process = 100 - 75.0 = 25.0 g
Now put all the given values in above equation, we get
Therefore, the time passed in days is 28.6 days.