Question

The ammonia solution that is purchased for a stockroom has a molarity of 15 M. Determine the volume of 15 M NH3(aq) that must be diluted to 500 mL to prepare 1.46 M NH3(aq). Answer in units of mL.

Answer 1

Answer: The volume of stock solution of ammonia that is needed is 48.67 mL

Explanation:

To calculate the volume of stock solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the stock ammonia solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted ammonia solution

We are given:

$M_1=15M\\V_1=?mL\\M_2=1.46M\\V_2=500mL$

Putting values in above equation, we get:

$15\times V_1=1.46\times 500\\\\V_1=\frac{1.46\times 500}{15}=48.67mL$

Hence, the volume of stock solution of ammonia that is needed is 48.67 mL