Accelerated motion such as a vehicle (car) or a moving item such as a (football thrown in the air)
as it is given that


now we will have

now the magnitude of this vector is given as


now to find the direction we can use




Answer:
the pressure drop for the water flow is greater than that for the air flow.
Explanation:
Detailed analysis of the problem is show below.
Newtons third law of motion is as below
every action has an equal and opposite reaction
#action=force
#reaction =another force
<u>Answer:</u>
The stopping car has negative acceleration.
<u>Explanation:</u>
We know acceleration is the rate of change of velocity. That is
Acceleration(a) = ( Final velocity - Initial velocity )/ Time taken.
Here Final velocity = 0 km/h( car stops) and initial velocity = 30 km/h
So acceleration = (0-30)/time = -30/ time
Time is always positive , so -30/time is negative, so the stopping car has negative acceleration.