Answer:
The induced voltage is 
Explanation:
From the question we are told that
The number of turns is 
The diameter is 
The initial magnetic field is 
The final magnetic field is 
The time taken is 
The radius is mathematically evaluated as

substituting values


Generally the induced emf is mathematically represented as

Where
is the change in magnetic flux of the wire which is mathematically represented as

=> 
Here 
since the axis of the coil is parallel to the field
Where A is the cross-sectional area of the coil which is mathematically represented as



So the induced emf
Here we substituted the values of 

Answer:
the impulse imparted to the ball is 4.158 kg.m/s
Explanation:
Please find attached image for diagram.
Given;
initial speed of the ball from point A, u = 54km/h = 15 m/s
angle of deflection of the ball along BOP, θ = 45⁰/2 = 22.5⁰
mass of the ball, m = 0.15 kg
the final speed of the ball along B, = u (in reverse direction)
The initial momentum of the ball, P₁ = mucosθ
The final momentum of the ball is P₂ in reverse direction to P₁.
the impulse imparted to the ball = change in momentum of the ball
J = ΔP = P₂ - P₁
J = mucosθ - (-mucosθ)
J = mucosθ + mucosθ
J = 2mucosθ
J = 2(0.15)15cos(22.5⁰)
J = 4.158 kg.m/s
Thus, the impulse imparted to the ball is 4.158 kg.m/s
<span>every magnet you interact with on a daily basis has two poles: a north and a south pole. Fridge magnets are permanent ferromagnets, and their magnetic field is generated by the alignment of their internal magnetic domains. A magnet sticks to a fridge not because the "fridge's pole" is opposite in sign to the "magnet pole" - the magnet always has two poles - but rather because the magnetic domains in the iron/steel of the fridge door align with the magnet field created by the permanent magnet, creating a 'new magnet" on the region it touches on the fridge. Both the north and south pole of a magnet will stick to a fridge, as well the side of the magnet containing both north and south poles.</span>