3 years ago

When a runner increases her speed from 75 m/s to 115 m/s in 25 s,her acceleration is _____

1 answer:

8 0

The acceleration would actually be 1.6 m/s^2. Acceleration= final velocity-initial velocity/time taken. When you do that formula it comes out to equal that.

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3 years ago

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3 years ago

It takes 130 J of work to compress a certain spring 0.10m. (a) What is the force constant of this spring? (b) To compress the sp

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Explanation:

Given that,

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(a) We know that work done in stretching the spring is as follows :

$W=\dfrac{1}{2}kx^2\\\\k=\dfrac{2W}{x^2}\\\\k=\dfrac{2\times 130}{(0.1)^2}\\\\k=26000\ N/m$

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So,

$W=\dfrac{1}{2}kx^2\\\\W=\dfrac{1}{2}\times 26000\times 0.2^2\\\\W=520\ J$

So, the new work is more than 130 J.

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3 years ago