Question

*Two objects have an elastic collision. Before the collision they approach one another with a velocity of 45 m/s. With what speed will they be separating after the collision?

Answer 1

In the elastic collision, the velocity of approach and velocity of separation is the same. The velocity of the separation after the collision will be 45 m/s.

What is collision?

The abrupt, violent coming together in direct contact of two bodies is known as the collision. a falling object and a floor are examples of collisions.

When the distance between two ships decreases while the bearings remain constant, a collision occurs.

Objects have an elastic collision. Before the collision, they approach one another V1​= V2​=45 m/sec

The velocity of the approach is found as;

$\rm = U_1-U_2 \\\\\ = 45-45 \\\\ = 0$

As we know,

$\rm e = \frac{U_2-U_1}{V_2-V_1}$

The velocity of separation is found as;

$\rm V_1-V_2$

and, e=1 for elastic collision.

$\rm U_1-U_2=V_2-V_1$

$\rm V_2-V_1 = 0 \\\ V_2 = V_1 = 45 \ m/sec$

In the elastic collision, the velocity of approach and velocity of separation is the same.

Hence the velocity of the separation after the collision will be 45 m/s.

To learn more about the collision refer to the link;

brainly.com/question/13138178

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