How much did the pressure drop in the storm's center from November 9, 1200z, until November 11, 0000z
1 answer:
The pressure dropped by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.
Using the attached map below, in the morning of November 9, the pressure situated at the storm's center = 1000 MB isobar located at the center.
Meanwhile, on November 11, 0000z the pressure situated at the storm's center = 976 MB isobar
The difference in this pressure is regarded as the pressure drop in the storm's center and it is determined as follows;
= 1000 MB - 976 MB
= 24 MB
Therefore, we can conclude that the pressure drop by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.
Learn more about pressure drop in an isobaric process here:
brainly.com/question/13089696?referrer=searchResults
You might be interested in
The energy of the ski lift at the base is kinetic energy:
where m is the mass of the ski lift+the people carried, and
is velocity at the base.
As long as the ski lift goes upward, its velocity decreases and its kinetic energy converts into potential energy. Eventually, when it reaches the top, its final velocity is v=0, so no kinetic energy is left and it has all converted into gravitational potential energy, which is
where
and h is the height at the top of the hill.
So, since the total energy must conserve, we have
and so
from which we find the height:
where m is the mass of the ski lift+the people carried, and
As long as the ski lift goes upward, its velocity decreases and its kinetic energy converts into potential energy. Eventually, when it reaches the top, its final velocity is v=0, so no kinetic energy is left and it has all converted into gravitational potential energy, which is
where
So, since the total energy must conserve, we have
and so
from which we find the height: