Hello,
In the left side, Mg and O are reactants... and MgO is the product....
<em>Hope</em><em> it</em><em> helped</em><em> you</em><em>.</em><em>.</em><em>.</em><em> </em><em>pls</em><em> mark</em><em> brainliest</em>
Answer:
mass Mg = 1.937 Kg
Explanation:
from periodic table for Mg:
⇒ molecular mass Mg = 24.305 g/mol
∴ mol ≡ 6.022 E23 atoms
⇒ mol Mg = (4.80 E25 atoms)×(mol/6.022 E23 atoms)
⇒ mol Mg = 79.708 mol
⇒ mass Mg = (79.708 mol)×(24.305 g/mol)
⇒ mass Mg = 1937.3 g
⇒ mass Mg = 1.937 Kg
<h3>
Answer:</h3>
138 g SO₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 2.16 moles SO₂
[Solve] grams (mass) SO₂
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of S - 32.07 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of SO₂ - 32.07 + 2(16.00) = 64.07 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
138.391 g SO₂ ≈ 138 g SO₂
<h3>
Answer:</h3>
78 L Cl₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
280 g Cl₂
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of Cl₂ - 2(35.45) = 70.90 g/mol
[STP] 1 mol = 22.4 L
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
78.4981 L Cl₂ ≈ 78 L Cl₂
Answer: only Br2.
Justification.
In a chemical reaction the element that gains electrons experiments a reduction in its oxidation state, that is why it is said that it is reduced.
So, to know what element is being reduced you need to calculate the oxidation states of the elements involved.
Here I indicate the oxidation states of each element if the reaction putting them inside parenthesis:
Reactants side Products side
K (0) K (1+)
Br (0) Br(1-)
So, K lost one electron, increasing its oxidation statefrom 0 to 1+, meaning that it is being oxidized.
And, each atom of Br gained one electron, reducing its oxidation state from 0 to 1-, meaning it is being reduced.
Therefore, the answer is that Br2 is the substance being reduced.