Write balanced equations and solubility product expressions for the following compounds cubr zn c2o4 agcro4

1 answer:

7 0

The solubility product expressions for the CuBr, ZnC₂O₄ and Ag₂CrO₄ will be represented as [Cu⁺][Br⁻], [Zn²⁺][C₂O₄²⁻] and [Ag⁺]²[CrO₄²⁻] respectively.

<h3>What is solubility product expressions?</h3>

The solubility product expression or constant is denoted by Ksp, and it is the equilibrium constant for a solid substance dissolving in an aqueous solution.

Balanced chemical reaction of CuBr is CuBr → Cu⁺ + Br⁻ and value of Ksp will be written as Ksp = [Cu⁺][Br⁻].
Balanced chemical reaction of ZnC₂O₄ is ZnC₂O₄ → Zn²⁺ + C₂O₄²⁻ and value of Ksp will be written as Ksp = [Zn²⁺][C₂O₄²⁻].
Balanced chemical reaction of Ag₂CrO₄ is AgCrO₄ → 2Ag⁺ + CrO₄²⁻ and value of Ksp will be written as Ksp = [Ag⁺]²[CrO₄²⁻].

Hence balanced equations with solubility product expressions will be shown above.

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Solid NaBr is slowly added to a solution that is 0.073 M in Cu+ and 0.073 M in Ag+.Which compound will begin to precipitate firs

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The concentration of $Ag^+$ when CuBr just begins to precipitate is, $1.34\times 10^{-6}M$

Percent of $Ag^+$ remains is, 0.0018 %

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$K_{sp}$ for CuBr is $4.2\times 10^{-8}$

$K_{sp}$ for AgBr is $7.7\times 10^{-13}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.

Now we have to calculate the concentration of bromide ion.

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$CuBr\rightleftharpoons Cu^++Br^-$