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Arte-miy333 [17]
2 years ago
10

Lake Michigan holds 1.3 x 1015 gallons of water. If just Chicago removed water from the

Chemistry
1 answer:
Lerok [7]2 years ago
5 0

1.3 x 10¹⁵ : 1.2 x 10⁹ = 1.083 x 10⁶

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Calculate the number of moles<br> 230 g of C2H5OH <br> 560 g of C2H4 <br> 0.640 g of SO2
Naddik [55]
Mass of C = 12g
mass of H = 1g
mass of O = 16g
mass of C2H5OH = 46g = 1 mole

1 mole of C2H5OH ------------ 46g
x moles of C2H5OH ----------- 230g
x = 5 moles of C2H5OH

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of C = 12g
mass of H = 1g
mass of C2H4 = 28g = 1 mole

1 mole of C2H4 -------------- 28g
x moles of C2H4 ------------- 560g
x = 20 moles of C2H4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of S = 32g
mass of O = 16g
mass of SO2 = 64g = 1 mole

1 mole of SO2--------------------- 64g
x mole of SO2 -------------------- 0,64g
x = 0,01 moles of SO2
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3 years ago
Determine a massa, em kg, de um material que está contida em um volume de 18L. Sabe-se que a densidade do material é de 0,9 g/cm
suter [353]
The question in English is "<span>Determine the mass, in kg, of a material that is contained in a volume of 18L. It is known that the material density is 0.9 g/cm 3"

Answer: 
</span>
We can use a simple equation to solve this problem. <span>
    d = m/v</span><span>

<span>Where </span>d <span>is the density, </span>m <span>is the mass and </span>v is the volume.

d = </span>0.9<span> g/cm³
m = ?
v = </span>18 L = 18 x 10³ cm³<span>

By applying the equation,
<span>    0.9 g/cm³ = m / </span></span>18 x 10³ cm³<span>
                  m = 0.9 g/cm³ x </span>18 x 10³ cm³<span> 
<span>                  </span>m = 16200 g
                  m = 16.2 kg

Hence, the mass of 18 L of material is 16.2 kg.</span>
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3 years ago
Can i get a snap i could send a link to, to do a few chem 1 assignments i could award more points
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A 0.400g sample of an unknown monoprotic acid is dissolved in water and titrated with a 0.150 M solution of NaOH. The equivalenc
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Answer:

Explanation:

12.036

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