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2 years ago

Lake Michigan holds 1.3 x 1015 gallons of water. If just Chicago removed water from the

Chemistry

1 answer:

Lerok [7]2 years ago

5 0

1.3 x 10¹⁵ : 1.2 x 10⁹ = 1.083 x 10⁶

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Which interaction produces dispersive forces by creating temporary dipoles that induce dipoles in other molecules?

pentagon [3]

Answer:

hydrogen bonds

Explanation:

dipoles + dipoles

5 0

3 years ago

Anyoneeee know thissss!?

Alekssandra [29.7K]

Answer:

C. 3 and 4

Explanation:

Count H's in formula (each has 4)

- Hope that helped! Please let me know if you need a further explanation.

3 0

3 years ago

Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a

horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound Amount

Ni 12.7 g

CO 1.98 g

$Ni(CO)_4$ 0.597 g

Calculate the value of the equilibrium constant.

<u>Answer:</u> The value of equilibrium constant for the reaction is 2448.1

<u>Explanation:</u>

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of $Ni(CO)_4$ = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

$\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M$

$\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M$

$\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M$

For the given chemical reaction:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

The expression of equilibrium constant for the reaction:

$K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}$

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1$

Hence, the value of equilibrium constant for the reaction is 2448.1

4 0

3 years ago

Check all statements below that are true.

docker41 [41]

Answer:

The answers are A,B,C.

Explanation: Just got it right on Edge 2020

3 0

3 years ago

What is an example of conduction

kicyunya [14]

Hello There!

Conduction is the transfer of heat from one particle of matter to another.

“I Have 3 Examples Of Convection Provided Below”

“A Pot Sitting On A Hot Burner”

“Picking Up A Hot Cup Of Coffee”

“Feet On Hot Sand”

5 0

3 years ago