Answer:
Explanation:
we can look for the final velocity of the object using the eqaution of motion as shown:
v² = u²+2gH
v is the final velocity
u is the initial velocity = 10m/s
g is the acceleration due to gravity = 9.81m/s²
H is the height of the object = 175m
Subxtitute the given parameters inti the formula and get v:
v² = 10²+2(9.81)(175)
v² = 100+3433.5
v² = 3533.5
v = √3533.5
v = 59.44m/s
Hence the final velocity of the object is 59.44m/s
Given:
Initial speed of the motorcycle (u) = 35 m/s
Final speed of the motorcycle (v) = 0 m/s (Complete Stop)
Maximum deceleration of the motorcycle (a) = -1.2 m/s²
Required Equation:

Answer:
By substituting values in the equation, we get:

Time taken by motorcycle to come to a complete stop (t) = 29.167 s
Changes in state of matter would be a physical change to whatever it is that you are changing so I think it would be B.Molecules because in order for something to change the molecules have to be moving apart from one another but I maybe wrong depending on what it is your looking at
Explanation:
Net force on the car= mass of the car × acceleration
F=1×10^3×4.5
=4.5×10^3 N
Answer:
1. 20.54m/s
2. 1.52s
Explanation:
QUESTION 1:
The speed the stone impact the ground is the final speed/velocity, which can be calculated using the formula:
v² = u² + 2as
Where;
v = final velocity (m/s)
u = initial velocity (m/s)
a = acceleration due to gravity (m/s²)
s = distance (m)
From the provided information, u = 5.65m/s, v = ?, s = 19.9m, a = 9.8m/s²
v² = 5.65² + 2 (9.8 × 19.9)
v² = 31.9225 + 2 (195.02)
v² = 31.9225 + 390.04
v² = 421.9625
v = √421.9625
v = 20.5417
v = 20.54m/s
QUESTION 2:
Using v = u + at
Where v = final velocity (m/s) = 20.54m/s
t = time (s)
u = initial velocity (m/s) = 5.65m/s
a = acceleration due to gravity (m/s²)
v = u + at
20.54 = 5.65 + 9.8t
20.54 - 5.65 = 9.8t
14.89 = 9.8t
t = 14.89/9.8
t = 1.519
t = 1.52s