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trapecia [35]
2 years ago
13

A collision is elastic only when kinetic energy and momentum are conserved through the collision. Group of answer choices True F

alse
Physics
1 answer:
alukav5142 [94]2 years ago
3 0

Answer:

Both momentum and kinetic energy are <u>conserved quantities</u> in elastic collisions.

Explanation:

An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision.

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Planet with the Great Red Spot
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Answer: jupiter

Explanation:

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2 years ago
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A 1300-kg car initially has a velocity of 22.2 m/s due south. It brakes to a stop over a 180 m distance.
Vaselesa [24]
The acceleration of the object which moves from an initial step to a full halt given the distance traveled can be calculated through the equation,
                                     d = v² / 2a
where d is distance, v is the velocity, and a is acceleration
Substituting the known values,
                                     180 = (22.2 m/s)² / 2(a)
The value of a is equal to 1.369 m/s²
The force needed for the object to be stopped is equal to the product of the mass and the acceleration.
                                      F = (1300 kg)(1.369 m/s²) 
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4 0
3 years ago
A baseball fan is 150.0 m from the home plate. how much time elapses between the instant the fan sees the batter hit the ball an
Artyom0805 [142]

Approximately 0.4373 seconds

Speed of sound at 20 degree C is roughly 343 meters/second

Speed of light = 3x10^8 or 300,000,000 meters/second

at 150.0 feet away you set it up as:

150.0/343 - 150/3x10^8

150.0/343 = 0.43731778

150/3x10^8 = 5x10^-7 or 0.0000005

Subtract 0.43731778 - 0.0000005

Answer is 0.43731728

Rounding would be approx. 0.4373

7 0
3 years ago
A student redid the experiment of mixing room temperature water and warm
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Answer:

I think B or C it won't lower so I'll go with B bc warm water is hotter than regular temp water

7 0
3 years ago
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The amplitude of a lightly damped oscillator decreases by 4.2% during each cycle. What percentage of the mechanical energy of th
ra1l [238]

Answer:

V= A ω      maximum KE of object in SHM

V2 / V1 = .958     ratio of amplitudes since ω is constant

KE2 / KE1 = 1/2 m V2^2 / (1/2 m V1^2) = (V2 / V1)^2

KE2 / KE1 = .958^2 = .918

So KE2 = .918 KE1 and .082 = 8.2% of the energy is lost in one cycle

6 0
2 years ago
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