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Verizon [17]
3 years ago
13

Is this right? I need help, thank you

Physics
1 answer:
erastovalidia [21]3 years ago
7 0

Velocity is correct, the symbol for acceleration is a. That is all I know.

(As in f=m*a)

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Unos amigos de 5 integrantes salen a comer, el primero pide un pollo a la brasa que cuesta S/50.00, el segundo un aeropuerto que
ser-zykov [4K]

Respuesta:

$138.39

Explicación:

Paso 1: Calcular el total que gastaron

El total que gastaron es igual a la suma de los que gastó cada uno.

$50.00 + $28.50 + $20.50 + $10.80 + $22.00 = $131.80

Paso 2: Calcular el 5% de $131.80

$131.80 × 5% = $6.59

Paso 3: Calcular el total que pagó con la tarjeta

A los $131.80 que gastaron debe sumarle los $6.59 por el uso de tarjeta.

$131.80 + $6.59 = $138.39

3 0
3 years ago
Which part of an atom is responsible<br>fon the flow of electricity?*​
svlad2 [7]

Answer:

The Electron

Explanation:

Electrons are how some atoms let electricity flow easily. If have closely bound electrons, then they are a bad conductor, or insulator. Atoms with loosely bound electrons allow electricity to easily flow, making these types of atoms great conductors. This is the case with most metals, where their electrons are very loose, making metals, like copper, great at transmitting electricity.

3 0
4 years ago
A motorist traveling at 17 m/s encounters a deer in the road 46 m ahead. If the maximum acceleration the vehicle’s brakes are ca
AveGali [126]

Answer:

t = 1.29 s

Explanation:

Maximum distance after which the motorist must have to stop is given as

d = 46 m

now the distance after which the vehicle will stop on applying breaks is given as

v_f^2 - v_i^2 = 2 a d

0 - 17^2 = 2(-6) d

d = 24.1 m

now remaining distance is given as

x = 46 - 24.1

x = 21.9 m

now reaction time is given as

t = \frac{x}{v}

t = \frac{21.9}{17}

t = 1.29 s

5 0
3 years ago
Suppose that a parallel-plate capacitor has circular plates with radius R = 25 mm and a plate separation of 4.7 mm. Suppose also
ozzi

Answer:

a) B_{max} = 1.784*10^{-12}

Explanation:

Given paraeters are:

R = 25 cm

d = 4.7 mm

f = 60 Hz

V_m = 160 V

a) V = V_msin(2\pi ft)

Where f = 60 Hz and V_m = 160 V

E =V/d= \frac{V_msin(2\pi ft)}{d}

For r = R

A = \pi R^2

Since \Phi_E = EA

\Phi_E=\frac{\pi R^2V_msin(2\pi ft) }{d}

From Ampere's Law:

\int B.ds = \mu_0\epsilon_0\frac{d\Phi_E}{dt} + \mu_0I_{encl} where I_{encl}=0

So at r = R,

B.2\pi R = \mu_0\epsilon_0\frac{d\Phi_E}{dt}\\B.2\pi R = \mu_0\epsilon_0\frac{2\pi^2fR^2V_mcos(2\pi ft)}{d}\\B = \frac{\mu_0\epsilon_0\pi fRV_mcos(2\pi ft)}{d}

For maximum B, cos(2πft) = 1. Hence,

B_{max}=\frac{\mu_0\epsilon_0\pi fRV_m}{d}=\frac{4\pi*10^{-7}*8.85*10^{-12}*\pi*60*0.025*160}{4.7*10^{-3}}=1.784*10^{-12} T

b) From r = 0 to r = R = 0.025 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fR^2V_m}{rd}

From r = R = 0.025 m to r = 0.1 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fRV_m}{d}

The plot is given in the attachment.

5 0
4 years ago
By how much does the gravitational potential energy of a 54-kg pole vaulter change if her center of mass rises about 4.0 m durin
kodGreya [7K]
<span>the gravational potential energy of anything on the ground is zero. When calculating potential energy you take height in meters and multiply it by the mass of the object in kilograms and the acceleration of gravity to get a new unit called Joules. Any object at ground level has a potential energy of zero newtons becuase anything multiplied by zero is zero. An object with mass of 54 kg, 4 meters above the ground has a gravitatinal potential energy of 2116.8 Joules.</span>
8 0
4 years ago
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