Answer:
Δx = 4.68 x 10⁻³ m = 4.68 mm
Explanation:
The distance between the consecutive maxima, in Young's Double Slit Experiment is given bu the following formula:
Δx = λD/d
So, the distance between the eighth order maximum and the fourth order maximum on the screen will be given as:
Δx = 4λD/d
where,
Δx = distance between eighth order maximum and fourth order maximum=?
λ = wavelength = 487 nm = 4.87 x 10⁻⁷ m
d = slit separation = 0.2 mm = 2 x 10⁻⁴ m
D = Distance between slits and screen = 48 cm = 0.48 m
Therefore,
Δx = (4)(4.87 x 10⁻⁷ m)(0.48 m)/(2 x 10⁻⁴ m)
<u>Δx = 4.68 x 10⁻³ m = 4.68 mm</u>
If two object experiences the same displacement at the same time, the two objects must have the same average velocity.
The average velocity of an object is defined as the change in displacement per change in time of motion. This can be written as follows;

If two object experiences the same displacement at the same time, it means that the change in displacement with time is constant.

Thus, we can conclude that if two object experiences the same displacement at the same time, the two objects must have the same average velocity.
Learn more here: brainly.com/question/23856383
Answer:
They both describe atoms as being made up of positive and negative matter.
Explanation:
In both Bohr's model and Thomson model, the atom consists of positively-charged matter and negatively-charged matter. However, the structure of the atom in the two models is totally different:
- in Thomson's model, the atom consists of a large sphere of uniform positive charge, and electrons (which are negatively charged) are scattered all around inside this sphere
- In Bohr's model, the atom consists of a small, positively charged nucleus, while the electrons (negatively charged) orbit around the nucleus in precise orbits.
Answer:
I = 33.04A
Explanation:
The magnetic field at the center of a loop of wire is proportional to the current flowing through the wire and inversely proportional to the radius
So therefore we have:
20/23 = I/38.0
We then solve for I
cross multiplying we have 20 x 38 = 23 x I
I = 20 x 38/ 23
I = 33.04A