Answer:
true
Explanation:
<h3><em>A healthy body will keep you in shape and less risk of getting sick</em></h3>
Wavelength = (speed) / (frequency)
Wavelength = (320 m/s) / (300 / sec)
Wavelength = (1 and 1/15) m/s
Answer:
Becuase 
So then we can conclude that:
And that makes sense since the force 
needs to accelerate the two masses and 
just need to accelerate 
.
So the best option for this case would be:
a. T1 > T2
See explanation below.
Explanation:
For this case we consider the system as shown on the figure attached.
Since the system is connected the acceleration for both masses are equal, that is 
From the second Law of Newthon we have that the force applied for the mass is 
and we know that the force acting on the x axis for the mass 2 is 
so then we have that 
Now when we consider the system of 
as a whole mass, this system have the same acceleration 
and on this case we will see that the only force acting on the entire system would be and then by the second law of Newton we have that:
And then if we compare and we see that :
Becuase
So then we can conclude that:
And that makes sense since the force needs to accelerate the two masses and just need to accelerate .
So the best option for this case would be:
a. T1 > T2
When matter changes state, many people think it goes from solid to liquid to gas, or vise versa. But the true fact is, matter doesn't change in any order.
Answer:
When the piano is dropped, the first force acting on it will be the gravitational force, that accelerates the piano at 9.8m/s^2 downwards.
As the piano accelerates, the velocity increases, now appears other force, the air resistance, that opposes to the motion of the piano.
As the velocity of the piano increases, also does the force that the air applies on the piano.
There is a point where the velocity of the piano is such that the air resistance is equal in magnitude, but in the opposite direction, to the force of gravity.
Then the net force on the piano is zero, which means that there is no acceleration, so the piano will keep falling down at constant velocity after this point.
