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Kamila [148]
2 years ago
15

Q1 A metal object has a mass of 8.37 g. When it was placed in a graduated cylinder containing 20.0 mL of water, the water level

rose to 23.1 mL. What is the density and identity of the metal? (see Table 3.1).
Q2 What is the mass of a solution that has a density of 0.775 g/mL and a volume of 50.0 mL?
Q3 What is the volume of a solution that has a specific gravity of 1.2 and a mass of 185 g?
Chemistry
1 answer:
Reika [66]2 years ago
6 0

Explanation:

<h2>I Forgot it please send a pic and tell me now Cause im lazy to Read ok</h2>
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Suppose the concentration of the standard stock solution is 50.04 ppm and that you delivered 4.60 mL of this standard stock solu
12345 [234]

Answer:

9.21 ppm

Explanation:

Considering

concentration_{working\ solution}\times Volume_{working\ solution}=concentration_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

concentration_{working\ solution}=?

Volume_{working\ solution}=25.00mL

Volume_{stock\ solution}=4.60mL

concentration_{stock\ solution}=50.04 ppm

So,  

concentration_{working\ solution}\times 25.00mL=50.04 ppm\times 4.60mL

concentration_{working\ solution}=\frac{50.04\times 4.60}{25.00}\ ppm=9.21\ ppm

4 0
3 years ago
List six elements with only 1 electron in an s orbital
Verdich [7]

Answer:

Lithium=Li2s^1\\Sodium=Na3s^1\\Potassium=K4s^1\\Rubidium=Rb5s^1\\Cesium=Cs6s^1\\Francium=Fr7s^1

Explanation:

When it comes to electron configuration and orbitals, it's important to first identify what exactly we are trying to identify. Below is a given example:

He1s^2

He=element

1=level

s=orbital

(exponent)^2=electrons

Looking at the periodic table, identify the alkali metal family on the periodic table, or group one elements:

Lithium=Li2s^1\\Sodium=Na3s^1\\Potassium=K4s^1\\Rubidium=Rb5s^1\\Cesium=Cs6s^1\\Francium=Fr7s^1

Notice how each configuration has an exponent of 1, representative of a single electron in their s-orbital.

6 0
3 years ago
Is it general principal that more abundant isotopes exist in
Nataly_w [17]

sjnsjshdjahshabbxbabsbasjsjjsjs

5 0
3 years ago
245 g water sample initially at at 32 oC absorbs 17 kcal of heat. What is the final temperature of water?
steposvetlana [31]

Answer:62.66°C or 235.66K

Explanation:Q=McpT, the energy was given in calories so you first convert to Joules by multiplying the value in calories by 4.184J.

17*4.184=71.128kJ.

71.128kJ=mcpT

71.128kJ=245*4.187*(T-Tm)

Tm is the final temperature of the mixture. The T is the temperature given which should be converted to Kelvin by adding 273...T=32+273=305K.

71128J=245*4.187*(305-Tm)

71128=312873.575-1025.815Tm

1025.815Tm=312873.575-71128

1025.815Tm=241745.58

Tm=241745.58/1025.815

Tm=235.66K

4 0
3 years ago
Which process is similar to binary fission?
elixir [45]
Fission is similar to mitosis because they both involve splitting. 

Answer: <span><span>d. mitosis</span></span>
8 0
3 years ago
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