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wariber [46]
1 year ago
8

The solubility of co in water at 0c and 1 atm co pressure is 0. 0354 mg of co in 1 ml of water. Calculate the moalrity of aqueso

us co solution at 2 atm co pressure.
Chemistry
1 answer:
Dmitriy789 [7]1 year ago
4 0

From all the calculations that were carried out, the concentration of 2atm is 0.0026 M.

<h3>What is molarity?</h3>

The term molarity is defined as the number of moles divided by the volume of the solution. Using the formula; C = kp where

  • C = concentration
  • k = constant
  • p = pressure

C =  0. 0354 * 10^-3 g/28 g/mol × 1000/1 L

C = 0.0013 M

k = C/p = 0.0013 M/1 atm

k = 0.0013 Matm-1

Now;

C =  0.0013 Matm-1 *  2 atm

C= 0.0026 M

Learn more about molarity: brainly.com/question/12127540

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What is the composition, in atom percent, of an alloy that contains a) 45.5 lbm of silver, b) 83.7 lbm of gold, and c) 6.3 lbm o
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Answer:

\% atAg=44.6\%\\\% atAu=44.9\%\\\% atCu=10.5\%

Explanation:

Hello,

In this case, for computing the atom percent, one must obtain the number of atoms of silver, gold and copper as shown below:

atomsAg=45.5lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{107.87gAg}*\frac{6.022x10^{23}atomsAg}{1molAg}=1.15x10^{26}atomsAg\\atomsAu=83.7lbm*\frac{453.59g}{1lbm}*\frac{1molAu}{196.97gAu}*\frac{6.022x10^{23}atomsAu}{1molAu}=1.16x10^{26}atomsAu\\atomsCu=6.3lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{63.55gCu}*\frac{6.022x10^{23}atomsCu}{1molCu}=2.71x10^{25}atomsCu

Thus, the atom percent turns out:

\% atAg=\frac{1.15x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.6\%\\\% atAu=\frac{1.16x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.9\%\\\% atCu=\frac{2.71x10^{25}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =10.5\%

Best regards.

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