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zhannawk [14.2K]
2 years ago
7

During a physical science lab investigating chemical reactions, several students placed a 30g antacid tablet in a 30g zip-lock b

ag. They recorded the masses of the tablet, and the bag. Then they added 50 grams of water and quickly sealed the bag. The tablet began to fizz and soon disappeared. The bag was filled with gas. If the mass of the liquid after the reaction is completed is still 50 grams, how much gas is produced? A) 30 grams B) 50 grams C) 80 grams D) 90 grams
Physics
2 answers:
ICE Princess25 [194]2 years ago
8 0
30 Grams would be your answer (I took the test and got it right)
lesantik [10]2 years ago
7 0

The answer is A) 30 grams

Just had this question

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Light traveling through air at 3.00 · 10^8 m/s reaches an unknown medium and slows down to 2.00 · 10^8 m/s. What is the index of
nataly862011 [7]
V 1= 3.00 · 10^8 m/s
v 2 = 2.00 · 10^8 m/s
The index of refraction:
n = v 1 / v 2 = 3.00 · 10^8 m/s : 2.00 · 10^8 m/s = 1.5
Answer:
The index of refraction of that medium is 1.5
5 0
3 years ago
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Starting from rest, a 5.00 kg steel sphere rolls down a frictionless ramp with a height of 4.00 m. What is the sphere's speed wh
elena-14-01-66 [18.8K]

Answer:

8.85437 m/s

Explanation:

m = Mass of sphere = 5 kg

h = Vertical height = 4 m

g = Acceleration due to gravity = 9.80 m/s²

Applying conservation of energy we get

\dfrac{1}{2}mv^2=mgh

\\\Rightarrow v=\sqrt{2gh}

\\\Rightarrow v=\sqrt{2\times 9.8\times 4}

\\\Rightarrow v=8.85437\ m/s

The sphere's speed when it reaches the bottom of the ramp is 8.85437 m/s

8 0
2 years ago
PHYSICS 50 POINTS PLEASE HELP
tangare [24]

Answer:

One way to look at Newton’s three laws of motion is this:

The third law states what forces are. That is, all forces are interactions between two different objects. If one object is interacting with another, then equal and opposite forces act on each object. So no force acts alone. When you exert a force on something, it is exerting the identical force back on you.

The first and second laws deal with the consequences of the forces that act on an object. The first law says that in the absence of a net force on an object, it simply continues doing whatever it was already doing. If it is at rest, it will remain at rest. If it is in motion, it will continue with that same motion - at constant speed and in the direction it was already traveling.

The second law says what happens if there is a net force on the object. In that case, the object accelerates - either by changing its speed, its direction, or both - in proportion and in the direction of the net force that acts on it. The amount of acceleration depends the object’s mass. That is, the larger the mass the smaller the acceleration for a given net force. The first and second laws can be summarized in the mathematical expression

F = ma

where F is the vector sum of all the forces that act on the object at any given moment (i.e., the net force), m is the mass of the object, and a is the acceleration of the object due to the net force at that moment - and is always in the same direction of the net force.

And notice that in a way, the first law is then “contained” within the second. That is, if the net force is zero on an object, then so is the acceleration. That is, either the object is (still) at rest or, if already in motion, the velocity didn’t change, in either case, the acceleration was zero.

Explanation:

4 0
2 years ago
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A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet
Serga [27]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The work done by the spring is = 0.27 J

Explanation:

Force = torque × length

Given

F = 9.13 N

length (L) = 5.91 cm  = 0.0591 m                         [Note 1 m = 100 cm ]

considering the formula above

          9.13 = k * 0.0591    where k denotes torque

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Energy Stored  = \frac{1}{2} k x^2

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                         = 0.27J  

8 0
3 years ago
I’ll give brainliest if it’s correct ;-;z
BlackZzzverrR [31]

Explanation:

what is the question? could you pls provide it

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