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alex41 [277]
2 years ago
9

Balance the following equation K+ O₂ - K₂O

Chemistry
1 answer:
bagirrra123 [75]2 years ago
6 0

Answer:

4K+O2=2K20

Explanation:

K+O2=K20

K+O2=2K20

4K+O2=2K20

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What is the luster of aluminum
Mamont248 [21]

Answer:

Luster of aluminum is Silver-White.

Explanation:

Aluminium is a Silver-White metal which is extracted from the Bauxite ore which can be reddish brown, white, tan, grey-white and tan-yellow in color and have the minerals like Gibbsite, Boehmite and Diaspore which are the minerals of the aluminium.

The Bauxite is the rock from which the Bauxite ore is extracted which have the minerals of the aluminum.

The luster of a metal is the color and shine of it and its shiny appearance.

Aluminium is a light weight metal but have a moderate hardness which makes a wider use of it. Aluminium is used in many places where the weight of the material is kept light but its hardness can be increased by mixing some other metals in it making hard alloy with lighter weight.

It is used in transportation vehicles, buildings, and many other places like Air crafts as the weight should be kept controlled to give a perfect lift to the Air craft.

3 0
3 years ago
What mass of butane in grams is necessary to produce 1.5×103 kJ1.5×103 kJ of heat? What mass of CO2CO2 is produced? Assume the r
saul85 [17]

32.8 g of Butane is required and 99.3 g of CO₂ is produced

<u>Explanation:</u>

The above mentioned reaction can be written as,

C₄H₁₀(g) + 13 O₂(g) → 4CO₂(g) + 5 H₂O(g)     where ΔH (rxn)= -2658 kJ

It is given that 1.5 × 10³ kJ of energy is produced, the original reaction says that 2658 kJ of heat is produced, which means that less than one mole of butane is used in the reaction.

That is

$\frac{1500}{2658}=0.564 \text { moles }    of butane reacted

Now this moles is converted into mass by multiplying it with its molar mass  = 0.564 mol × 58.122 g / mol

                     = 32.8 g of butane.

Mass of CO₂ produced = 0.564 ×44.01 g /mol × 4 mol

                                        = 99.3 g of CO₂

Thus 32.8 g of Butane is required and 99.3 g of CO₂ is produced

7 0
3 years ago
What is the first step of a ladybug during the growth and development process​
Sunny_sXe [5.5K]

Answer:

Damian here! (ノ◕ヮ◕)ノ*:・゚✧

The newly hatched larva is in its first instar, a developmental stage that occurs between molts. It feeds until it grows too big for its cuticle, or soft shell, and then it molts. After molting, the larva is in the second instar. Ladybug larvae usually molt through four instars, or larval stages, before preparing to pupate.

Explanation:

hope this helps? :))

7 0
4 years ago
Complete the transmutation equation below. Assume that there is only one unknown product. Np93239→Pu94239+?
aliya0001 [1]
I have attached the answer. hopefully, i read the problems correctly. let me know if I did not.

both problems are an example of beta decays. when an atoms' atomic number is increased by one. this is symbolized with -1 e

5 0
3 years ago
Why is there such a large jump and ionization energy between the second and third ionization energy‘s for magnesium?
Romashka [77]
The second ionization energy of Mg is larger than the first because it always takes more energy to remove an electron from a positively charged ion than from a neutral atom. The third ionization energy of magnesium is enormous, however, because the Mg2+ ion has a filled-shell electron configuration.
5 0
3 years ago
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