The balanced equation is:
2NaCl + 2 H2o → 2 NaOH + Cl2 + H2
1- we put 2 NaCl to balance Cl2 on the other side.
2- we put 2 NaOH to balance Na
3- We put 2 H2O to balance H & O on the to sides
Answer:
The answer to your question is P2 = 170.9 torr
Explanation:
Data
Volume 1 = 12.1 l Volume 2 = 21.1 l
Temperature 1 = 241 °K Temperature 2 = 298°K
Pressure 1 = 546 torr Pressure 2 = ?
Process
To solve this problem use the combined gas law.
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = T1V1T2 / T1V2
-Substitution
P2 = (241 x 12.1 x 298) / (241 x 21.1)
-Simplification
P2 = 868997.8 / 5085.1
-Result
P2 = 170.9 torr
Answer:
1.7 M
Explanation:
Concentration is the number of moles of solute dissolved in 1 L of solution
Concentration = number of moles of solute / volume of solution
Number of moles of solute needs to be calculated first
Mass of methanol - 12.5 g
Molar mass of methanol - 32 g/mol
Number of methanol moles - 12.5 g / 32 g/mol = 0.39 mol
Therefore concentration is = 0.39 mol / 0.230 L = 1.7 mol/L
Concentration is 1.7 M
Answer:
The volume of hydrochloric acid increases.
Explanation:
- Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
- Increasing the volume of water vapors:
will increase the the concentration of the products side, so the reaction will be shifted to the left side (backward) to suppress the increase in the concentration of water vapors by addition.
So, The volume of hydrochloric acid increases, the rate of backward reaction increases, the rate of forward reaction decreases, and the volume of chlorine decreases.
<em>So, the right choice is: The volume of hydrochloric acid increases.</em>
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