Answer:
ΔE(work)= 692 Kj/mole e⁻ = 4.32 x 10²⁴ eV/mole e⁻
Explanation:
ΔE = hc/λ = (6.63 x 10⁻³⁴j·s)(2.99792 x 10⁸m/s)/(1.73 x 10⁻⁷m) = 1.15 x 10⁻¹⁸j/e⁻ x 6.023 x 10²³ e⁻/mole = 691,999 j/mole e⁻ = 692 Kj/mole e⁻ x 6.24 x 10²¹ eV/KJ = 4.32 x 10²⁴ eV/mole e⁻
N=N₀*2^(-t/T)
N₀=200 g
T=10 d
t=30 d
N=200*2^(-30/10)=25 g
25 g will remain
Answer/Explanation:
letters are used as a sign of chemical symbols in today's time
MAINLY CONCENTRATED IN THE INDUSTRY.
The reaction will be spontaneous if Gibb free energy is negative, according the following relation:
G = H - T*S
where G is Gibbs free energy, T is change of enthalpy , T is temperature and S is change of entropy
In the case of ammonia:
G = -93000 - 356*(-198) = -93000 + 70488 = -22512 j/mol
As G < 0 then the reaction is spontaneous.
