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Varvara68 [4.7K]
2 years ago
6

PLSS HELP AND I WILL GIVE BRAINLY TO THE ONE WHO ANSWERS CORRECTLY

Physics
1 answer:
Ierofanga [76]2 years ago
7 0

The potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

<h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The energy in terms of the charge and potential difference is;

E= qV

60=5 C × V

V= 12 V

The electric current is found as;

\rm I= \frac{q}{t} \\\\ I= \frac{5}{1.25}\\\\ I=4 \ A

From the ohm's law;

V=IR

12=4 ×R

R=3Ω

If the voltage is constant and the resistance is doubled, then the new electric current is half of the previous condition;

\rm I'=\frac{I}{2} \\\\ I'=\frac{4}{2} \\\\\ I'=2 \ A

Hence, the potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

To learn more about the resistance, refer to the link;

brainly.com/question/20708652

#SPJ1

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Pls help, me, i nees to submit now
Pavlova-9 [17]

Answer:

12m

Explanation:

To obtain the answer to the question given, we must observe the characteristics of image formed by a plane mirror.

The image formed by a plane mirror have the following characteristics:

1. Laterally inverted.

2. Same distance as the object from the mirror.

3. Same height as the object.

4. Virtual.

With the above information, we can calculate the distance between the boy and his image as follow:

Initially:

Object distance (u) = 4m

Image distance (v) = 4m

The boy moved 2m away, therefore:

Object distance (u) = 2 + 4 = 6m

Image distanc(v) = 2 + 4 = 6m

The distance between the boy and his image will be the sum of his distance (u) and image distance (v) i.e (u + v)

The distance between the boy and his image = 6 + 6 = 12m

Therefore, the distance between the boy and his image is 12m.

6 0
2 years ago
A truck traveled 400 meters north in 80 seconds and then it traveled 300 meters east in 70 seconds. The magnitude of the average
Varvara68 [4.7K]

Answer:

3.3m/s

Explanation:

You first get the total time (80 + 70 = 150s).

Then you would find the displacement of the truck. To do that you would do component method (vector addition), so since its a right triangle (North and East), displacement is 400^2 + 300^2 = d^2.

d= 500m.

So now that you have displacement and time, you can find the velocity:

v=d/t

v=500/150

v=3.3

5 0
2 years ago
At 20 degrees Celsius, conducting wires made of different materials have the same length and the same diameter. Which wire has t
DENIUS [597]

Answer:

Aluminium

Explanation:

Aluminium has the least resistance since It has 3 free electrons per atom. Its resistivity is low compared to other metals provided in the choices (gold, nichrome, tungsten). Low resistivity of metals means a high conductance of the metal referred to.

7 0
3 years ago
How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v
777dan777 [17]
The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
W= qV_i - qV_f
where q is the charge of the proton, q=1 e = 1.6\cdot 10^{-19}C, with e being the elementary charge, and V_i = +125 V and V_f = -55 V are the initial and final voltage.

Substituting, we get (in electronvolts):
W=e(125 V-(-55 V))=180 eV
and in Joule:
W=(1.6 \cdot 10^{-19})(125 V-(-55V))=2.88 \cdot 10^{-17}J

5 0
3 years ago
A space vehicle is traveling at 3760 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The
almond37 [142]

Answer:

3688 km/h

Explanation:

Given:-

- The speed of vehicle relative to earth, vs_e = 3760 km/h

- The relative speed of command and motor, v_c/m = 90 km/h

- The mass of command = m

- The mass of motor = 4m

Find:-

What is the speed of the command module relative to Earth just after the separation?

Solution:-

- Consider the space vehicle as a system that detaches itself into two parts ( command and motor ). We will assume that the gravitational pull due to Earth on the space vehicle is negligible. With that assumption we have our system in isolation. We will apply the principle of conservation of linear momentum on the system as follows:

             Initial momentum = Final momentum

                                       Pi = Pf

                  M*vs_e = m*vc_e + 4m*vm_e

Where,

                  M = m + 4m = 5m

                  vc_e = Velocity of command relative to earth

                  vm_e = Velocity of motor relative to earth  

- We will develop a relation of velocities of command and motor in the frame of earth as follows:

                  vm_e =  v_c/m + vc_e        

- Substituting (vm_e) from Equation 2 into Equation 1, we have:

                  5m*vs_e = m*vc_e + 4m*(v_c/m + vc_e)

                  5m*vs_e = 5m*vc_e + 4m*(v_c/m)

- Solve for vc_e:

                  5m*vs_e -  4m*(v_c/m) = 5m*vc_e

                   vs_e - 0.8*(v_c/m) = vc_e

- Plug in values and evaluate vc_e:

                  vc_e = 3760 - 0.8*(90)

                  vc_e = 3,688 km/h

5 0
3 years ago
Read 2 more answers
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