draw x,y axes.
x is deg M
y is deg C
0 of deg M = -38.9degC
100 >>> 356.9
draw st line 0,-38.9 to 100,356.9
slope is 3.95
line eq is degC = 3.95xdegM-38.9
set degC to 100. find degM
degM about 35 for boiling water
Explanation:
One of the takeaways of the General Theory of Relativity (GTR) was that the light can be curved because of the gravity of a massive object. Einstein had proposed the idea of <em>space-time</em> fabric. Every object having mass will create depression in this fabric. Heavier the object, bigger the depression. Thus when light will pass near a heavy object lets say our Sun, it will deflect. He also gave mathematical formula to calculate the deflection.
The same was proved during the Total Solar Eclipse of 29 May 1919. Two scientists named Arthur Eddington and Frank Dyson conducted an experiment. In this eclipse the Sun was to be in front of Hyades in Taurus constellation. They took the measurement of stars of Hyades visible during the eclipse and then compared them with the actual readings. The deflection was clearly visible and the amount of deflection was very close to the values predicted by General Theory of Relativity. Thus they proved the theory right.
<u>We are given:</u>
Weight on Earth = 300 N
Value of g on the planet = 4 ft/s²
<u>Converting to m/s: </u>
4 ft/s² * (1 m / 3.3 ft) = 13.2 m/s²
<u>Mass of the object:</u>
We know that:
Weight = Mass * g
<em>replacing the given values</em>
300 = Mass * 9.8 [g = 9.8 m/s²]
Mass = 300/9.8
Mass = 30.6 kg <em>(approx</em>
<u>Weight on the other Planet:</u>
Weight = Mass * g(on that planet)
Weight = 30.6 kg * 13.2 m/s²
Weight = 403.92 N
Answer:
d ) is the answer.
Explanation:
Let M be the mass and R be the radius of each of ball , hoop and disc.
kinetic energy of sphere - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and
V = ωR
kinetic energy of sphere - 1/2 MV² + 1/2 x 2/5 MR² ω²
= 1/2 MV² + 1/5 MR² ω²
MV² ( 1/2 + 1/5 )
= .7 MV²
kinetic energy of Disk - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and
V = ωR
kinetic energy of Disk - 1/2 MV² + 1/2 x 1/2 MR² ω²
= 1/2 MV² + 1/4 MR² ω²
MV² ( 1/2 + 1/4 )
= .75 MV²
kinetic energy of Hoop - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and
V = ωR
kinetic energy of hoop - 1/2 MV² + 1/2 MR² ω²
= 1/2 MV² + 1/2 MR² ω²
MV² ( 1/2 + 1/2 )
= MV²
Kinetic energy is largest in case of hoop and least in case of sphere . So hoop will go up to the highest point and sphere will go to a height which will be least among the three.