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Tema [17]
3 years ago
8

In an experiment, 1 mol of propane is burned to form carbon dioxide and water.

Physics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

5 moles of O2are required, you can see it in your equation.

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Pressure is always measured in comparison to a standard pressure.<br> True<br> False
irakobra [83]

Answer:

true

Explanation:

8 0
3 years ago
Which of the following is a type of renewable energy?
harina [27]
The answer is C Hydroelectric
3 0
3 years ago
Read 2 more answers
At which of the above boundries is sea floor destroyed
Slav-nsk [51]
The continental crust
Hope it helps!!
7 0
3 years ago
What are possible units for impulse? Check all that apply.
Neporo4naja [7]

Units of impulse: N • s, kg • meters per second

Explanation:

Impulse is defined in two ways:

1)

Impulse is defined as the product between the force exerted in a collision and the duration of the collision:

I=F\Delta t

where

F is the force

\Delta t is the time interval

Since the force is measured in Newtons (N) and the time is measured in seconds (s), the units for the impulse are

[I] = [N][s]

So,

N • s

2)

Impulse is also defined as the change in momentum experienced by an object:

I=\Delta p

where the change in momentum is given by

\Delta p = m\Delta v

where m is the mass and \Delta v is the change in velocity.

The mass is measured in kilograms (kg) while the change in velocity is measured in metres per second (m/s), therefore the units for impulse are

[I]=[kg][m/s]

so,

kg • meters per second

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
Read 2 more answers
Suppose your surface body temperature averaged 90 degrees F. How much radiant energy in W/m^2 would be emitted from your body?
Debora [2.8K]

493 \; \text{W}\cdot \text{m}^{-2}.

<h3>Explanation</h3>

The Stefan-Boltzmann Law gives the energy radiation <em>per unit area</em> of a black body:

\dfrac{P}{A} = \sigma \cdot T^{4}

where,

  • P the total power emitted,
  • A the surface area of the body,
  • \sigma the Stefan-Boltzmann Constant, and
  • T the temperature of the body in degrees Kelvins.

\sigma = 5.67 \times 10^{-8} \;\text{W}\cdot \text{m}^{-2} \cdot \text{K}^{-4}.

T = 90 \; \textdegree{}\text{F} = (\dfrac{5}{9} \cdot (90-32) + 273.15) \; \text{K} = 305.372 \; \text{K}.

\dfrac{P}{A} = \sigma \cdot T^{4} = 5.67 \times 10^{-8} \times 305.372^{4} = 493\; \text{W}\cdot \text{m}^{-2}.

Keep as many significant figures in T as possible. The error will be large when T is raised to the power of four. Also, the real value will be much smaller than 493\; \text{W}\cdot \text{m}^{-2} since the emittance of a human body is much smaller than assumed.

5 0
3 years ago
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