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Blizzard [7]
2 years ago
13

A rock once contained 1.0 mg of uranium-238, but now contains only 0.25 mg. Given that the half-life for uranium-238 is 4.5 x 10

^9 (4.5 billion) years, how old is the rock?​
Physics
1 answer:
Darina [25.2K]2 years ago
5 0

Answer:

9 x 10 ^9 yrs    ( 9 billion years <=====older than Earth !)

Explanation:

.25 = 1.0 (1/2) ^n

.25 / 1.0 =   = (1/2 )^n

log .25 =  n log 1/2

n = 2 half lives

2 * 4.5 x 10^9 =   9 x 10 ^ 9 yrs

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8 0
3 years ago
If the frequencies of two component waves are 24 Hz and 20 Hz, they should produce _______ beats
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Your answer should be 4Hz

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3 years ago
Venus is often called Earth's "twin." Describe TWO ways in which Earth and Venus are similar and TWO ways in which Earth and Ven
insens350 [35]

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8 0
3 years ago
Suppose that a nascar race car is moving to the right with a constant velocity of +86 m/s. What is the average acceleration of t
Stels [109]

(a) As the car is moving with constant velocity, it means the rate change of velocity does not change, therefore the average acceleration of the car is zero.

Thus, there is no acceleration, when velocity is constant.

(b) Average acceleration,

a =\frac{ v-u}{\Delta t}

Here, v is final velocity and u is the initial velocity and \Delta t is the time interval.

As twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed, therefore

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6 0
3 years ago
Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 83 vol% carbide
velikii [3]

Answer:

  k_max = 31.82 w/mk

  k_min  = 17.70 w/mk

Explanation:

a) the maximum thermal conductivity is given as

k_{max} = k_m*v_m + k_p*v_p

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.17

v_p = proportion of carbide in the cement = 0.83

            = 66*0.17 + 28*0.83

           k_max = 31.82 w/mk

b) the minimum thermal conductivity is given as

k_{min} = \frac{k_{carbide}* k_{metal}}{k_{metal} v_{carbide} +k_{metal} v_{carbide}}

          = \frac{28+66}{28*0.17 +66*0.83}

       k_min  = 17.70 w/mk

7 0
3 years ago
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