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3 years ago

What must always be included on the graph

Physics

1 answer:

Nookie1986 [14]3 years ago

4 0

Clearly visible data points and appropriate labels on each access that include units

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The illuminance On a surface is six lux and the surface is 4 meters from the light source what is the intensity of the source

Liula [17]

Answer : 96 candelas

Explanation : Luminous intensity is a quantity of light that is emitted by a light source with a solid angle in a particular direction.

We know the formula of luminous intensity

Luminous intensity = illuminance x distance from light source

$L_{v} = E_{v}\times d^{2}$

$L_{v} = 6\times 16\ candelas$

$L_{v} = 96\ candelas$

So, the intensity of the source will be 96 candelas.

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3 years ago

HEYYYYYY HEYYYYYYYYY

weeeeeb [17]

Answer: i dont know what is happening but I'm answering with another HEEEYYYYYYY HEYYYYYYYY

Explanation:

8 0

3 years ago

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Tina and her puppy are tugging on a rope each pulling on opposite ends when is tina doing work ? When is Tina doing work ?

Varvara68 [4.7K]

Explanation : Tina is doing work all of the time because whiles she’s pulling and allowing the rope to be pulled her body using muscles to keep herself upright and a firm grip on the rope.

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3 years ago

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A heavy stone of mass m is hung from the ceiling by a thin 8.25-g wire that is 65.0 cm long. When you gently pluck the upper end

Triss [41]

Answer: m= 35.6 kg

Explanation:

For finding the mass of the stone we have the formula

v= $\sqrt{\frac{Tension}{Linear. Mass. density} }$

Here, Tension= m*g = m*9.81

and linear mass density= $\frac{8.25 g}{65 cm}$

Linear mass density= $\frac{8.25*10^-3}{65*10^-2}$

Linear mass density= 0.0127 kg/m

Velocity= $2*\frac{l}{t}$

Velocity= 2 * $\frac{65*10^-2}{7.84}$

Velocity= 165.8 m/s

So putting all these values in equation we get

v= $\sqrt{\frac{Tension}{Linear. Mass. density} }$

165.8= $\sqrt{\frac{m*9.81}{0.0127} }$

Solving we get

m= 35.58 kg

or m= 35.6 kg

3 0

3 years ago

In our lab experiment on Ohm's law, the power supply is connected to a circuit containing one resistor, and a direct current of

lapo4ka [179]

Answer: (A) 3.0=A

Explanation: In order to explain this problem we have to use the OHM law, given by: V=R*I

Besides, we have to consider the resitance equivalent for a parallel connection. This is given by:

1/Re=1/R1+1/R2

If we connect the same resistance, the equivalent resistance is R/2.

Initlally the current is 1.5 A when one resistance is connected to the batttery. When a second resistance with the same value is connected in parallel to the battery, we have V=Re*Ifinal= (R/2)*Ifinal

also we know that V=R*Iinitial so Iinitial=V/R

then Ifinal= 2*V/R=2*Iinitial

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3 years ago