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2 years ago

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What produces the magnetic field of an electromagnet?

1 answer:

andrew11 [14]2 years ago

4 0

An electromagnet is a magnet whose magnetic field is created when electricity is flowing.

<h2>What is an electromagnet?</h2>

A device consisting of an iron or steel core that is magnetized by electric current in a coil that surrounds it.

<h2>What is magnetic field?</h2>

Magnetic force is defined as the space surrounding a magnet in which magnetic force is exerted.

<h2>What is electricity?</h2>

A form of energy created by charged or moving <em>electrons</em> or <em>protons</em>.

<h2>What does it mean when electricity is flowing?</h2>

The movement of energy is called a flow. The flow of electricity through a wire can be thought of as being similar to the flow of water through a pipe. Electricity usually flows in specially protected wires, but it can also move around using many other objects.

<h2>How does a magnetic field and the flow of electricity relate?</h2>

The electromagnetic force produces two related phenomena: electricity and magnetism. They combine to generate electromagnetism. A magnetic field is created by a moving electric charge. Electric charge movement is induced by a magnetic field, resulting in an electric current.

<h2>What produces a magnetic field? </h2>

Electric charges in motion. Charged particles in motion have both an electric field and magnetic field associated with them.

<h2>How does an electromagnet work?</h2>

An electric current flows through a coil of wire. This produces a magnetic field in the wire. The sides of the coil that carry current at 90 degrees to the magnetic field experience a force as they interact with the magnetic field.

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3 years ago

How much force is required to accelerate a 2kg mass at 3 m/s2? answer key?

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3 years ago

Use the Bohr model to address this question. When a hydrogen atom makes a transition from the 5 th energy level to the 2nd, coun

iris [78.8K]

Answer:

A. 2.82 eV

B. 439nm

C. 59.5 angstroms

Explanation:

A. To calculate the energy of the photon emitted you use the following formula:

$E_{n1,n2}=-13.4(\frac{1}{n_2^2}-\frac{1}{n_1^2})$ (1)

n1: final state = 5

n2: initial state = 2

Where the energy is electron volts. You replace the values of n1 and n2 in the equation (1):

$E_{5,2}=-13.6(\frac{1}{5^2}-\frac{1}{2^2})=2.82eV$

B. The energy of the emitted photon is given by the following formula:

$E=h\frac{c}{\lambda}$ (2)

h: Planck's constant = 6.62*10^{-34} kgm^2/s

c: speed of light = 3*10^8 m/s

λ: wavelength of the photon

You first convert the energy from eV to J:

$2.82eV*\frac{1J}{6.242*10^{18}eV}=4.517*10^{-19}J$

Next, you use the equation (2) and solve for λ:

$\lambda=\frac{hc}{E}=\frac{(6.62*10^{-34} kg m^2/s)(3*10^8m/s)}{4.517*10^{-19}J}=4.39*10^{-7}m=439*10^{-9}m=439nm$

C. The radius of the orbit is given by:

$r_n=n^2a_o$ (3)

where ao is the Bohr's radius = 2.380 Angstroms

You use the equation (3) with n=5:

$r_5=5^2(2.380)=59.5$

hence, the radius of the atom in its 5-th state is 59.5 anstrongs

8 0

3 years ago

A 55 newton force applied on an object moves the object 10 meters in the same direction as the force. What is the value of work

kifflom [539]

Answer: Option D: 5.5×10²Joules

Explanation:

Work done is the product of applied force and displacement of the object in the direction of force.

W = F.s = F s cosθ

It is given that the force applied is, F = 55 N

The displacement in the direction of force, s = 10 m

The angle between force and displacement, θ = 0°

Thus, work done on the object:

W = 55 N × 10 m × cos 0° = 550 J = 5.5 × 10² J

Hence, the correct option is D.

3 0

3 years ago