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elena-14-01-66 [18.8K]
3 years ago
9

Match the description with the type of front

Physics
1 answer:
Inga [223]3 years ago
4 0

Answer: Do you need help with how to get the photograph?

Explanation:It's in the comments if you want to known have a good day!

:)

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What instrument can be used to show the shape of a sound wave?
mafiozo [28]
"Oscilloscope"  can be used to show the shape of a sound wave

Hope this helps!
7 0
3 years ago
A scientist conducting a field investigation records measurements of very low pressure and high relative humidity at the top of
Ivan

Answer:

Please find the answer in the explanation

Explanation:

Given that a scientist conducting a field investigation records measurements of very low pressure and high relative humidity at the top of a mountain.

Since a weather map indicates that a warm front is approaching the mountain, according to the conventional current, the warm front is approaching because the weather must have been in higher relative humidity in cool air.

The warm front is approaching to replace it so that the cool air can conventionally replace the warmth air too.

The condition the scientists will most likely observe at the top of the mountain will be high relative humidity.

5 0
3 years ago
Behavioral Adaptations: Behavior that animals begin life with that helps them meet their needs is called ________.
Arturiano [62]
I believe the blank would simply be behaviour adaptations. Behavioural adaptations are behaviours that organisms demonstrate to help them better survive and reproduce in a habitat. Hope that helps!!
6 0
3 years ago
Read 2 more answers
Pushing a rock from a hill top is called
wariber [46]
It's called "utter disregard for the safety and welfare
of the people standing at the bottom of the hill".
6 0
3 years ago
A jogger hears a car alarm and decides to investigate. While running toward the car, she hears an alarm frequency of 872.10 Hz.
Nata [24]

Answer:

v = 4.18 m/s

Explanation:

given,

frequency of the alarm = 872.10 Hz

after passing car frequency she hear = 851.10 Hz

Speed of sound = 343 m/s

speed of the jogger = ?

speed of the

v_f = \dfrac{872.10-851.10}{2}

v_f =10.5\ Hz

v_o = 872.1 - 10.5

V_0 = 861.6\ Hz

The speed of jogger

v = \dfrac{v_1 \times 343}{v_0}-343

v = \dfrac{872.1 \times 343}{861.6}-343

v = 4.18 m/s

5 0
2 years ago
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