Answer:
Find the answer in the explanation
Explanation:
Given that a ball is dropped from rest from the top of a building of height h. At the same instant, a second ball is projected vertically upward from ground level, such that it has zero speed when it reaches the top of the building.
a. When do the two balls pass each other?
The the balls will pass each other before the second ball reach half of the height of the building. Because the velocity of the second ball decreases as it goes upwards while the velocity of the first ball increases as it moves downwards
b. Which ball has greater speed when they are passing?
The first ball of course because the velocity of the second ball decreases as it goes upwards while the velocity of the first ball increases as it moves downwards
c. What is the height of the two balls when they are passing?
Taking the height from the bottom of the building upward
Since the two balls meet at a certain point, they will both have the same height.
Time taken by the car to travel 300 miles is 4.615 hours.
<h3>What is speed?</h3>
The speed of any moving object is the ratio of the distance traveled and the time taken to cover that distance.
Given is the distance d = 300 miles and the speed s = 65 miles/hour, then the time taken t will be
s=d/t
65 = 300/t
t= 4.615 hours
Thus, time taken by the car to travel 300 miles is 4.615 hours.
Learn more about speed.
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To develop this problem it is necessary to apply the concepts related to the Frequency according to the Period. Frequency is the number of repetitions per unit of time of any periodic event. The period is the length of time of each repetitive event, so the period is the reciprocal of the frequency.
The frequency of the metronome in seconds would then be
Since the frequency is inversely proportional to the period then
The correct answer is B. 375ms
Answer:
the answer is D
Explanation:
if you read the paragraph and question number 4 it tells you the answer wich is d
