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Tatiana [17]
2 years ago
7

What tissue does the skin of chicken wing attach to

Physics
1 answer:
stiks02 [169]2 years ago
7 0
Piggly wiggly farttttttttttttttt corn beef beefed tripled beefed up on a Tuesday

Chacken Wangs

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What is the magnitude of velocity for a 2000 kg car possessing 3000 kgm/s of momentum
Alex

For this case we have that by definition, the momentum is given by:

p = mv

Where,

  • <em>m: mass </em>
  • <em>v: speed </em>

Therefore, replacing values we have:

3000 = (2000) v

From here, we clear the value of the speed:

v = \frac {3000} {2000}\\v = 1.5 \frac {m} {s}

Answer:

The magnitude of velocity is:

v = 1.5 \frac {m} {s}

4 0
3 years ago
Read 2 more answers
When a mass M hangs from a vertical wire of length L, waves travel on this wire with a speed V. What will be the speed of these
Zigmanuir [339]

Answer:

a)  v = 0.7071 v₀, b) v= v₀, c)  v = 0.577 v₀, d)   v = 1.41 v₀, e)  v = 0.447 v₀

Explanation:

The speed of a wave along an eta string given by the expression

          v = \sqrt{ \frac{T}{ \mu } }

where T is the tension of the string and μ is linear density

a) the mass of the cable is double

          m = 2m₀

let's find the new linear density

          μ = m / l

iinitial density

          μ₀ = m₀ / l

final density

          μ = 2m₀ / lo

          μ = 2 μ₀

we substitute in the equation for the velocity

initial            v₀ = \sqrt{ \frac{T_o}{ \mu_o} }

with the new dough

                    v = \sqrt{ \frac{T_o}{ 2 \mu_o} }

                    v = 1 /√2  \sqrt{ \frac{T_o}{ \mu_o} }

                    v = 1 /√2 v₀

                    v = 0.7071 v₀

b) we double the length of the cable

If the cable also increases its mass, the relationship is maintained

              μ = μ₀

   in this case the speed does not change

c) the cable l = l₀ and m = 3m₀

we look for the density

           μ = 3m₀ / l₀

           μ = 3 m₀/l₀

           μ = 3 μ₀

            v = \sqrt{ \frac{T_o}{ 3 \mu_o} }

            v = 1 /√3  v₀

            v = 0.577 v₀

d) l = 2l₀

            μ = m₀ / 2l₀

            μ = μ₀/ 2

           v = \sqrt{ \frac{T_o}{ \frac{ \mu_o}{2} } }

           v = √2 v₀

            v = 1.41 v₀

e) m = 10m₀ and l = 2l₀

we look for the density

             μ = 10 m₀/2l₀

             μ = 5 μ₀

we look for speed

             v = \sqrt{ \frac{T_o}{5 \mu_o} }

             v = 1 /√5  v₀

             v = 0.447 v₀

5 0
2 years ago
What statements correctly describe theories
elixir [45]

Theories result from several repeated experiments.

Theories explain observations and hypotheses.

Theories may be revised over time.

Explanation:

Scientific theories are purely explanations into an observation and hypothesis. The are general binding explanations that have been developed from several tests.

  • Theories are products of different stages of experiments in their own regard.
  • For a theory to be accepted by the scientific community, its hypothesis statement must be:
  1. Testable
  2. Repeated
  3. Falsifiable
  • Based on new evidence, a theory may be revised with time. One of such is the Dalton's atomic theory with a modern atomic theory version now.

Learn more:

Experiments brainly.com/question/5096428

#learnwithBrainly

8 0
2 years ago
A deer with a mass of 146kg is running head on toward you with a speed of 17 m/s. You are going north. Find the momentum of the
Pavel [41]
Momentum = Mass * Velocity = 146 * 17 = 2482  kgm/s
6 0
3 years ago
Read 2 more answers
At a circus, a human cannonball is shot from a cannon at 15m/s at an angle of 40° above horizontal. She
Citrus2011 [14]

Answer:

a

The height is   H  = 6.74 \  m

b

The horizontal distance is  D  = 23.74 \  m

Explanation:

From the question we are told that

  The speed is  v  =  15 \  m/s

  The angle is  \theta  =  40^o

   The height of the cannon from the ground is  h  =  2 m

  The distance of the net from the ground is k  =  1 m

 

Generally the maximum height she reaches is mathematically represented as  

     H  =  \frac{v^2 sin^2 \theta }{2 *  g }  +  h

=>    H  =  \frac{(15)^2 [sin (40)]^2 }{2 * 9.8}  +  2

=>    H  = 6.74 \  m

Generally from kinematic equation  

    s = ut + \frac{1}{2} at^2

Here s is the displacement which is mathematically represented as

         s  =  [-(h-k)]  

    =>  s =  -(2-1)

    =>  s  = -1 m

There reason why s =  -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half

     a =  -g = -9.8

    u  =  v sin (\theta)

So

    -1 = (vsin 40 )t + \frac{1}{2} * (-9.8) t^2

=>  -4.9t^2 + 9.6418t + 1 = 0

using  quadratic formula to solve the equation we have

    t  =  2.07 \  s

Generally distance covered along the horizontal is  

   D  =  v cos (40) *  2.07

=>   D  =  15 cos (40) *  2.07

=>   D  = 23.74 \  m

7 0
3 years ago
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