Law of conservation of energy says that, <span>Energy cannot be created or destroyed, but can change from one form to another. Hope this helps!</span>
Answer:
Finding time period of SHM from equation of displacement
Explanation:
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Say for example I've got the equation of a SHM as:
x=Acos(ωt+ϕ)
where A is the amplitude.
How do I find the time period of this motion?
I tried by finding the second order differential of the given equation.
a=d2xdt2=−Aω2cos(ωt+ϕ)
Comparing it with the general equation for acceleration a=−ω2x, we can find ω from here.
But that is where the problem is coming. It makes no sense if I write ω=ωA−−√.
What is the correct method to find the time period of the SHM? What am I missing?
There is a very simple mistake in your math. Notice A is part of x, it is factored so you'll get to ω=ω again. If you want to find a meaning to ωT=2π, consider the fact that cos (or sin) are periodic functions with period 2π. Hence, every time you have a time difference such that ω(t1−t2)=2π you are back at the same point. Hence the period is given by ωT=2π.
Answer:
Explanation:
It is given that,
Taking the cross product of v and v such that,
|w| = 13.92
Let is the unit vector normal to the plane containing u and v. So,
Hence, this is the required solution.
Answer:
I think it effects it by how the fire being a chemical reaction since it has gas in it, it effects it by how the water pputs it out, and it stopping the chemical reactions
Explanation:
.5mv^2 is the energy equation so .5(25kg)(5m/s)^2 so it’s 312.5 joules