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Vera_Pavlovna [14]
3 years ago
10

If the velocity of a moving object decreases from 60 m/s to 30 m/s, what happens to its momentum?

Physics
2 answers:
amid [387]3 years ago
6 0

Hello!

momentum is p=mv so if the velocity is decreased by a factor of 2, which is 1/2 the value, then the momentum of that object will decrease by the same factorial.

Hope this helps, any questions please ask. Thank you!

sergeinik [125]3 years ago
5 0

Qualitatively the momentum is the amount of motion contained in the body.

Quantitatively momentum is the product of mass and velocity of the body.

Mathematically momentum= mass×velocity

                                       i.e p=m×v

where p denotes the momentum.

As per the question the initial velocity of the particle is given as [u]=60 m/s

The final velocity of the particle is given as [v]=30 m/s

Let the mass of the particle is m kg

The initial momentum p_{1} =m*u

                                                  =60m kg m/s

the final momentum p_{2} =m*v

                                                   =30m kg m/s

Hence the change in momentum is given as -

                                   p_{2} -p_{1} =[30m -60m] kg m/s

                                                              = -30m kg m/s

Here the minus sign indicates the loss of momentum

Hence the momentum is decreased by twice as the velocity is decreased by twice.

In general if velocity is decreased by m times ,then the momentum is decreased by m times also.


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quester [9]

Answer:

A police radar gun uses X-band microwave radiation at a frequency of 13.1 GHz. Microwaves travel at the speed of light, or 3x108 m/s. Since the frequency shift will be small for practical car speeds and difficult to detect, the shifted frequency is compared to the original frequency, and the resulting beat frequency is used to determine the speed of the car.

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Explanation:

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3 years ago
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ArbitrLikvidat [17]

Answer:

Light refracts when its speed changes as it enters a new medium.

Explanation:

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7 0
3 years ago
An airplane starts from rest and accelerates at 10.8 m/s2 . what is its speed at the end of a 400 m long runway?
Cloud [144]

The final speed of an airplane is v = 92.95 m/s

The rate of change of position of an object in any direction is known as speed i.e. in other word, Speed is measured as the ratio of distance to the time in which the distance was covered.

Solution-

Here given,

Acceleration a= 10.8 m/s2 .

Displacement (s)= 400m

Then to find final speed of airplane v=?

Therefore from equation of motion can be written as,

v²=u²+ 2as

where, u is initial speed, v is final speed ,a is acceleration and s is displacement of the airplane. Therefore by putting the value of a & s in above equation and (u =0) i.e. the initial speed of airplane is zero.

v²= 2×10.8 m/s²×400m

v²=8640m/s

v=92.95m/s

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1 year ago
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belka [17]

Answer:

The speed of the ball was, v = 3 m/s

Explanation:

Given data,

The time period of the ball, t = 8 s

The distance the ball rolled, d = 24 m

The velocity of an object is defined as the object's displacement to the time taken. The formula for the velocity is,

                              v = d / t      m/s

Substituting the given values in the above equation,

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A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)​
Illusion [34]

The work done against gravity is 100 J

Explanation:

The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:

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\Delta h is the change in height of the object

For the object in this problem, we have:

m = 5 kg

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\Delta h = 2 m

Substituting into the equation,

W=(5)(10)(2)=100 J

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