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Vera_Pavlovna [14]
3 years ago
10

If the velocity of a moving object decreases from 60 m/s to 30 m/s, what happens to its momentum?

Physics
2 answers:
amid [387]3 years ago
6 0

Hello!

momentum is p=mv so if the velocity is decreased by a factor of 2, which is 1/2 the value, then the momentum of that object will decrease by the same factorial.

Hope this helps, any questions please ask. Thank you!

sergeinik [125]3 years ago
5 0

Qualitatively the momentum is the amount of motion contained in the body.

Quantitatively momentum is the product of mass and velocity of the body.

Mathematically momentum= mass×velocity

                                       i.e p=m×v

where p denotes the momentum.

As per the question the initial velocity of the particle is given as [u]=60 m/s

The final velocity of the particle is given as [v]=30 m/s

Let the mass of the particle is m kg

The initial momentum p_{1} =m*u

                                                  =60m kg m/s

the final momentum p_{2} =m*v

                                                   =30m kg m/s

Hence the change in momentum is given as -

                                   p_{2} -p_{1} =[30m -60m] kg m/s

                                                              = -30m kg m/s

Here the minus sign indicates the loss of momentum

Hence the momentum is decreased by twice as the velocity is decreased by twice.

In general if velocity is decreased by m times ,then the momentum is decreased by m times also.


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grin007 [14]

The resistance of the circuit is 0.496 \Omega

Explanation:

We can solve the problem by applying Ohm's law, which gives us the relationship between current, potential difference and resistance in a circuit:

V=RI

where

V is the potential difference

R is the resistance

I is the current

For the circuit in this problem,

V = 12.6 V

I = 25.4 A

Re-arranging the equation, we can solve for the resistance:

R=\frac{V}{I}=\frac{12.6}{25.4}=0.496 \Omega

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8 0
3 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen
bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

f_{a} =(\frac{v+v_{c} }{v} )f_{s} (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s} (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s

b) Substitute eq. 1 in eq. 2:

f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz

7 0
3 years ago
Canola oil is less dense than water, so it floats on water, but its index of refraction is 1.47, higher than that of water. When
kupik [55]

Answer:

therefore critical angle c= 69.79°

Explanation:

Canola oil is less dense than water, so it floats over water.

Given n_{canola}= 1.47

which is higher than that of water

refractive index of water n_{water}=1.33

to calculate critical angle of light going from the oil into water

we know that

sinc= \frac{n_{water}}{n_{canola}}

now putting values we get

sinc= \frac{1.33}{1.47}

c= sin^{-1}(\frac{1.33}{1.47} )

c=69.79°

therefore critical angle c= 69.79°

8 0
3 years ago
A scientist designed a foam container to help keep frozen foods from melting. Which best explains how the foam works?
FrozenT [24]
I think the answer should be D.<span>It reduces the amount of thermal energy that is transferred from outside to inside the container. </span>
6 0
3 years ago
Read 2 more answers
The uniform rods AB and BC weigh 24 ky and kg, respectively,and the small wheel at C is of negligible weight. If the wheel ismov
victus00 [196]

The velocity of pin B after rod AB has rotated through 90* is vb = 3.2549 m/s.

<h3>What is Potential and Kinetic energy?</h3>

Potential energy is the energy that is stored in any item or system as a result of its location or component arrangement. The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles inside a system or an item.

mass of rod, mab = 2.4kg

mass of rod, mbc = 4kg

conservation of energy

T_{1}  + V_{1} = T_{2}  + V_{2}

h_{ab}  = h_{bc}  = 0.18m

potential energy at position 1,

V1 = m_{ab} gh_{ab}  + m_{bc} gh_{bc}

V1 = 2.5 * 9.81 * 0.18 + 4 * 9.81 * 0.18

V1 = 11.30112

kinetic energy T1 at position 1 is zero

potential energy at position 2 is zero

K.E at position 2,

T_{2} = \frac{1}{2} l_{ab} w^{2}_{ab} +  \frac{1}{2} m_{bc} v^{2}_{G} +  \frac{1}{2} lw^{2}_{bc}

l_{ab} =\frac{m_{ab} l^{2}_{ab}  }{3}

= 1/3 *4 * (0.36)²

=0.10368kg m²

l =\frac{m_{bc} l^{2}_{bc}  }{12}

= 1/12 *4 * (0.6)²

=0.12kg m²

on putting the values in above equation we get,

T₂ = 1.0667vb²

0 + 11.30112 = 1.0667vb² + 0

vb = 3.2549 m/s

to learn more about Kinetic and potential energy go to - brainly.com/question/18963960

#SPJ4

5 0
1 year ago
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