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Natasha2012 [34]
3 years ago
13

You have an evacuated container of fixed volume and known mass and introduce a known mass of a gas sample. measuring the pressur

e at constant temperature over time, you are surprised to see it slowly dropping. you measure the mass of the gas-filled container and find that the mass is what it should be - gas plus container - and the mass does not change over time, so you do not have a leak. part a suggest an explanation for your observations. suggest an explanation for your observations. the gas undergoes a chemical reaction that has fewer gas particles in products than in reactants. pressure is directly proportional to number of particles, so the pressure decreased. when the gas was plased into container it obtained some extra kinetic energy. after some time this energy was expend, so the speed of the particles reduced and the pressure dropped the gas undergoes a chemical reaction that has more gas particles in products than in reactants. pressure is directly proportional to number of
Chemistry
1 answer:
balandron [24]3 years ago
4 0
Answer is: <span>the gas undergoes a chemical reaction that has fewer gas particles in products than in reactants. pressure is directly proportional to number of particles, so the pressure decreased.
Ideal gas law: PV = nRT. If amount of substance decreased, pressure also decreased.</span>
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Answer:

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3 years ago
What is the molar mass of a substance
aleksandrvk [35]
<span>47.88 g/mol is the awsner your welcome</span>
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Read 2 more answers
The ksp of lead iodide is 7.1 × 10-9. a chemical engineer adds 0.0025 mol of ki to a solution of 0.00004 mol pb(no3)2 in 500 ml
inn [45]
Answer is: n<span>o, because the ion product is less than the Ksp of lead iodide. </span>

Chemical dissociation 1: KI(s) → K⁺(aq) + I⁻(aq).
Chemical dissociation 2: Pb(NO₃)₂(s) → Pb²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s).
Ksp(PbI₂) = 7.1·10⁻⁹.
V = 500 mL ÷ 1000 mL/L = 0.5 L.
c(KI) = c(I⁻) = 0.0025 mol ÷ 0.5 L.
c(I⁻) = 0.005 M.
c(Pb(NO₃)₂) = c(Pb²⁺) = 0.00004 mol ÷ 0.5 L.
c(Pb²⁺) = 0.00008 M.
Q = c(Pb²⁺) · c(I⁻)².
Q = 8·10⁻⁵ M · (5·10⁻³ M)².
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8 0
2 years ago
While in Europe, if you drive 109 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per lite
MrRissso [65]

Answer:

The amount is x  =  113.3 \  dollars

Explanation:

From the question we are told that

     The  distance traveled per day is  l  =  109\ km =  \frac{109}{1.609}  =  67.74 \  mi

    The  cost of one liter is  c =  1.10 \ euros/liter = 1.10  *  1.26  = 1.36 \ dollars/liter

     The car's  gas mileage is  b =  22.0 \ mi/gal

Generally the amount of distance covered in one week is evaluated as

      z =  67.74 * 7

       z = 474.18 \  mi

The  amount of gas used in one week by the car is mathematically represented as  

       k  = \frac{ z}{ b}

=>    k  = \frac{ 474.18}{ 22}

=>      k  =  22 \ gal

converting to liters

          k =  22 *  3.78541=83.28 \ liters

Thus the amount spent on gas in one week is  

          x =  k *  c

=>      x  =  83.28 *  1.36

=>      x  =  113.3 \  dollars

 

5 0
3 years ago
How does an elements period number related to the number of the energy level of its valence electrons?
Mrac [35]
<span>There is a direct correlation between the period number and the energy level for valence electrons. For example, the H and He elements, in period 1, have their outer electrons in the energy level "1". This continues down the rows: all the elements in period 2 have their principal energy level as n = 2, period 3 has n = 3, and so on.</span>
3 0
3 years ago
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