Answer:
the IUPAC name of the following compound is 2,3 dimethyl pentane!
Answer : C
Because $6.65 multiplied by 4 hours equals $26.60
Answer:
The molar mass of the liquid 62.89 g/mol
Explanation:
Step 1: Data given
Mass of the sample = 0.1 grams
Temperature = 70°C
Volume = 750 mL
Pressure = 0.05951 atm
Step 2: Calculate the number of moles
p*V = n*R*T
n = (p*V)/(R*T)
⇒ with n = the number of moles gas = TO BE DETERMINED
⇒ with p = The pressure = 0.05951 atm
⇒ with V = The volume of the flask = 750 mL = 0.750 L
⇒ with R = The gasconstant = 0.08206 L*atm/K*mol
⇒with T = the temperature = 70 °C = 343 Kelvin
n = (0.05951 *0.750)/(0.08206*343)
n = 0.00159 moles
Step 3: Calculate molar mass
Molar mass = mass / moles
Molar mass =0.1 gram / 0.00159 moles
Molar mass = 62.89 g/mol
The molar mass of the liquid 62.89 g/mol
Answer:
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Explanation:
The equilibrium equation showing the dissociation of weak acid is:
![HA (aq) + H_{2}O(l) A^{-}(aq) + H_{3}O^{+}(aq)](https://tex.z-dn.net/?f=%20HA%20%28aq%29%20%2B%20H_%7B2%7DO%28l%29%20%3C%3D%3D%3E%20A%5E%7B-%7D%28aq%29%20%2B%20H_%7B3%7DO%5E%7B%2B%7D%28aq%29%20%20%20%20%20)
is the equilibrium constant for this equation, which is referred to as the acid dissociation constant.
value will determine the acidic strength of the acids. Greater the value, more will be the acidity.
Calculating the
value from given equilibrium concentrations:
![K_{a} = \frac{[H_{3}O^{+}][A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%20K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BH_%7B3%7DO%5E%7B%2B%7D%5D%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D%20%20%20%20%20%20)
= ![\frac{(2.00*10^{-4})(2.00*10^{-4})}{0.220}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%282.00%2A10%5E%7B-4%7D%29%282.00%2A10%5E%7B-4%7D%29%7D%7B0.220%7D%20%20%20%20)
= ![1.82 * 10^{-7}](https://tex.z-dn.net/?f=%201.82%20%2A%2010%5E%7B-7%7D%20%20)