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liubo4ka [24]
2 years ago
12

A sample of propane, C3H8, occupies 1.73 mL when the pressure is 320 torr at 30 C. What is the volume at STP

Chemistry
1 answer:
hammer [34]2 years ago
8 0

The volume of the sample of propane at STP is 0.62 mL.

<h3>What is volume?</h3>

Volume is the amount of space that a substance or object occupies.

To calculate the volume of gas at STP, we apply the formula below.

Formula:

  • PV/T = P'V'/T'................. Equation 1

Where:

  • P = Initial pressure of gas
  • V = Initial volume of gas
  • T = Initial temperature of gas
  • P' = Standard pressure (SP)
  • T' = Standard temperature (ST)
  • V' = Volume of gas at STP.

Make V' The subject of the equation

  • V' = PVT'/P'T.............. Equation 2

From the question,

Given:

  • P = 320 torr
  • V = 1.73 mL
  • T = 30 °C = (30+273) K = 303 K
  • P' = 760 torr
  • T' = 273 K

Substitute these values into equation 2

  • V' = (320×1.73×273)/(760×303)
  • V' = 0.62 mL

Hence, the volume of the sample of propane at STP is 0.62 mL.
Learn more about volume here: brainly.com/question/26507715

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<u>Explanation:</u>

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PV=nRT

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P = pressure of the gas = 1.00 bar

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n = number of moles of gas = ?

R = Gas constant = 0.0831\text{ L. bar }mol^{-1}K^{-1}

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Putting values in above equation, we get:

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To calculate the heat released of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

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q = amount of heat released = ?

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\Delta H_{rxn} = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ

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