Answer:
pursuing a goal
Explanation:
Since there are no answer choices provided I would say that this is an example of pursuing a goal. This is basically all of the tasks and struggles that an individual must go through in order to finally achieve a certain goal. It also involves gradually breaking barriers and pushing forward by increasing the complexity of the tasks until you are able to break through all of them to reach the end-goal that you have been striving for. Which is exactly what John has been doing in this scenario by gradually increasing his running time.
Answer:
25 m/s
Explanation:
This question can be solved using equation of motion
where
v is the final velocity
u is the initial velocity
s is the distance covered while moving from initial to final velocity
a is the acceleration
_____________________________________________
Given
box moved for distance of 62.5 m
Friction slows the box at –5.0 m/s2----> this statement means that there is deceleration , speed of truck decreases by 5 m/s in every second until the box comes to rest. Friction causes this deceleration.
thus in this problem
a = -5.0 m/s2
V = 0 as body came to rest due to friction deceleration
u the initial velocity we have to find
the initial velocity of box will be the same as speed of truck, as the box was in the truck and hence box will pick the speed of truck.
so if we find speed of box, we will be able get sped of truck as well.
using equation of motion
Thus, initial speed with the truck was travelling was 25 m/s.
Answer:
the period T of whole motion should be twice the value for half at he bottom so T is 0.2sec.
w is angular frequency
formula:2π/T
now k is spring constant
F/R-->mw²
putting values:70*(2π/0.2)²
=4.9x10⁶
so we can say that SHM is not affected by the amplitude of the bounce.
Answer:
0.0196 j
Explanation:
i) The formula for kinetic energy is as follows: 0.5*m*v^2
ii) Since we have all the values all that's left is to plug them into the equation
iii) First, WE MUST, Convert grams into kgs as this is the SI unit of mass so 2.45/1000
iv) All that's left now is to plug it into the equation so:
0.5* (s.45/1000)*(4^2)
v) Lastly we add the unit joules at the end as we're talking about energy
Hope this was useful! :)
Answer:
ωf =1.78 rev/s
Explanation:
it is a non elastic collision, so conservation of angular momentum is used. and there id no friction
I₁ωi₁ + I₂ωi₂ = (I₁ + I₂)ωf
ωi₁ = 2.0 rev/s*(2π) rad/rev = 4.0π rad/s
assume ωi₂ = 0
Sol the equation to wf
ωf = (½m₁r₁²)ωi₁ / (½m₁r₁² + ½m₂r₂²)
ωf = (m₁r₁²)*ωi₁ / (m₁r₁² + m₂r₂²)
ωf = (5.0kg*(0.18m)²)4.0 π rad/s / ((5.0kg*(0.18m)²) + (3.1*(0.08m)²))
ωf =11.19 rad/s/ 2π
ωf =1.78 rev/s