Answer:1.084
Explanation:
Given
mass of Pendulum M=10 kg
mass of bullet m=5.5 gm
velocity of bullet u
After collision let say velocity is v
conserving momentum we get


Conserving Energy for Pendulum
Kinetic Energy=Potential Energy

here
from diagram
therefore

initial velocity in terms of v

For first case 

for second case 

Therefore 


i.e.
Answer:
<h2>
The answer is </h2><h2>
a. 5g/mL</h2>
Explanation:
Given data
mass m= 45g
volume v= 9mL
we know that density=m/v
substituting our given data we have

What is Density?
The Density of a body can be defined as the ratio of mass to volume,
or
Density, mass of a unit volume of a material substance. The formula for density is
,
where d is density,
M is mass, and
V is volume.
Density is commonly expressed in units of grams per cubic centimetre.
Answer:
223.25
Explanation:
The thermal conductivity of an object is defined as the measure or the ability of the object to transfer heat or conduct heat through its body.
In the context, the thermal conductivity of the material is given as

And it is given that :
1 Btu = 1055 J
1 ft = 0.3048 m

We know that 1 h = 3600 s
So the thermal conductivity of the material in
is :
Thermal conductivity :


= 223.25
There are several ways they interact with each other.
Mechanically: Erosion, Mass movement, Sedimentation
Hostile work environment sexual harassment can be verbal, visual or physical. This statement is true.